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Vesna [10]
3 years ago
8

Identify the error below. Then, solve the equation correctly.

Mathematics
1 answer:
lions [1.4K]3 years ago
3 0

Answer:

Error: +3x should be -3x

x should equal 3

Step-by-step explanation:

In this problem, you have to pay attention how values are transferred from one side to the other. This includes paying attention t the signs.

In 3x + 4 = 8x - 11, you want to try an keep all the values positive

      3x   +   4   =   8x  -   11

   <em> - 3x                - 3x</em>

                  4   =   5x  -   11

                 +11               +11      <--This part of the equation was correct.

                  15  =  5x

                  /5       /5   <--This part of the equation should result in dividing by <em>5</em>

                  3   =  x

Hope this helps!

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Solve image below:
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Answer: x=\frac{6}{-3y+8}

Step-by-Step Explanation:

Let's solve for x.

\frac{x-2}{3y-5} =\frac{x}{3}

Step 1: Multiply both sides by 3y-5.

x-2=\frac{3xy-5x}{3}

Step 2: Multiply both sides by 3.

3x-6=3xy-5x

Step 3: Add -3xy to both sides.

3x-6+-3xy=3xy-5x+-3xy

-3xy+3x-6=-5x

Step 4: Add 5x to both sides.

-3xy+3x-6+5x=-5x+5x

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Step 5: Add 6 to both sides.

-3xy+8x-6+6=0+6

-3xy+8x=6

Step 6: Factor out variable x.

x(-3y+8)=6

Step 7: Divide both sides by -3y+8.

\frac{x(-3y+8)}{-3y+8}=\frac{6}{y-3y+8}

x=\frac{6}{-3y+8}

Answer:

x=\frac{6}{-3y+8}

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