Answer:
37 is the smallest positive integer n such that n(n+1)(n+2) is divisible by 247.
Step-by-step explanation:
First we will find the prime factors of 247:
247 = 13 x 19 (which are both prime).
So now we need to find a number (the smallest one) that is of the form (n)(n+1)(n+2) (the product of three consecutive numbers) and that is divisible by both 13 and 19 (and therefore divisible by 247)
Let's take a look at the multiples of 13: 13, 26, 39, 52...
Let's take a look at the multiples of 19: 19, 38, 57...
We can see that the first time we have two multiples close together are the 38 (for 19) and the 39 (for 17).
So, if our number has both 38 and 39 as factors, then it will be divisible by 247.
However, we need not two but three consecutive numbers, and since we want the number to be the smallest positive integer, we will add 37 (since our other choice would be to add 40 and that would make the number bigger) and thus our number is (37)(38)(39) or in other words (37)(37 + 1)(37 + 2) and therefore this is the smallest positive number such that n(n+1)(n+2) is divisible by 247.
(0, 4)
(-1, -3)
(2, -3)
For a 90 degrees clockwise rotation, the rule is (y, -x)
The answer is 18. You add 5 to both sides of the equation. the 5 cancels out. You are left with 2/3x=12. Then you divide 12 by 2/3 to get x. 12 divided by 2/3 is 18
Answer:
x=-3/5y+3
Step-by-step explanation:
Let's solve for x.
5x+3y=15
Step 1: Add -3y to both sides.
5x+3y+−3y=15+−3y
5x=−3y+15
Step 2: Divide both sides by 5.
5x/5 = -3y+15/5
Answer
x=-3/5y+3
Write an equation. To do this, make one integer equal to x, and the other equal to x+1. Set these equal to 149. Your equation should read x+(x+1)=149. Solve. To do this, add the two x's together. Your equation is now 2x+1=149. Get your x's alone. First, subtract 1 from both sides. Now the equation is 148=2x. Divide both sides by 2 to get x alone. You now have x=74. Plug this value back into the original equation to find your value for the other integer, and you have the two integers as 74 and 75. Hope this helps!
