The answer is; The frequency for allele O = 0.7746 while that of o = 0.2254
Well use the hardy Weinberg equation of a population at equilibrium; p2 + 2pq + q2 = 1
In our case, p2 will be 60/100 = 0.6; therefore p = square-root of 0.6 = 0.7746
Remember also that the frequencies of alleles of the same gene add up to one (1); i.e p + q = 1
Therefore q = 1 – 0.7746 = 0.2254
Answer:
Reproductive isolation is the very factor that causes the development of what we call "species" according to the biological species concept. The reason cats and dogs are different species is that they can't mate, so we call them "reproductively isolated."
Answer:
e commence is the right and ILY answer in the ptions