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statuscvo [17]
3 years ago
11

the length of a rectangle exceeds its width by 11 inches, and the area is 80 square inches. What are the length and width of the

rectangle?
Mathematics
2 answers:
astra-53 [7]3 years ago
5 0
Width is 5 inches, length is 16 inches
PolarNik [594]3 years ago
5 0

Factors of 80:

1 x 80 [ Difference is 79]

2 x 40 [Difference is 38]

4 x 20 [Difference is 16]

5 x 16 [Difference is 11]

8 x 10 [Difference is 2]


From the information above, we can conclude that the <u>length is 16 </u>and the <u>width is 5</u>, which gives us a difference if 11.

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Alicia, Jamar, and Tia collect dimes for charity. Alicia collects (3k+4) dimes. Jamar collects twice as many dimes as Alicia. Ti
oee [108]

Answer:

33k+32

Step-by-step explanation:

Assign Variables :

Alicia- A

Jamar- J

Tia- T

Write equations :

A = (3k+4)

J= 2(3k+4)

T=4(5+6k)

Simplify equations:

A= 3k+4

J= 6k+8

T= 20+24k

Add:

(3k+4)+(6k+8)+(20+24k)

3k+6k+24k+8+20+4

33k+32

I hope this helps :)

7 0
3 years ago
Units of Length
Lyrx [107]

Answer:

1 foot = 0.3048 meters

Step-by-step explanation:

1 foot = 12 inches

1 inch = 2.54 centimeters

1 foot = 12 * 2.54 = 30.48 centimeters

1 meter = 0.01 centimeters

1 foot = 0.3048 meters

3 0
3 years ago
Read 2 more answers
Georgio drives 10 miles east, then 16 miles north, then 4 miles north again. Find the distance from his starting point to his en
larisa86 [58]

Answer:

22.36 mile.

Step-by-step explanation:

Please see attached photo for explanation.

In the attached photo, y is the distance between starting point and the end point.

Thus we can obtain the value of y by using the pythagoras theory as show below:

Note: y is the longest side other wise known as the Hypothenus.

y² = 10² + 20²

y² = 100 + 400

y² = 500

Take the square root of both side

y = √500

y = 22.36 mile

Therefore, the distance between the starting point and the end point is 22.36 mile

3 0
4 years ago
Write in function notation;<br> y= 5x + 2
Sav [38]
X= -2/5 + y/5 solve for x by simplying both sides of the equation, then isolating the variable
5 0
3 years ago
Read 2 more answers
which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x
pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case  if the point (2,80) satisfied the exponential function

<u>case A</u>  f(x)=4(x^{5})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(2^{5})=128

128\neq 80

therefore

the exponential function  f(x)=4(x^{5}) not passes through the point (2,80)

<u>case B</u>  f(x)=5(x^{4})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(2^{4})=80

80=80

therefore

the exponential function f(x)=5(x^{4}) passes through the point (2,80)

<u>case C</u>  f(x)=4(5^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=4(5^{2})=100

100\neq 80

therefore

the exponential function f(x)=4(5^{x}) not passes through the point (2,80)

<u>case D</u>  f(x)=5(4^{x})

For x=2 calculate the value of y in the equation and then compare with the y-coordinate of the point

so

f(2)=5(4^{2})=80

80=80

therefore

the exponential function f(x)=5(4^{x}) passes through the point (2,80)

therefore

<u>the answer is</u>

f(x)=5(x^{4})

f(x)=5(4^{x})

7 0
3 years ago
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