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Ratling [72]
3 years ago
6

What is 8,663,943,526 rounded to the nearest million? A. 8,663,000,000 B. 8,663,944,000 C. 8,664,000,000 D. 9,000,000,000

Mathematics
1 answer:
maksim [4K]3 years ago
8 0
The answer is 
<span>C. 8,664,000,000</span>
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ALS OTHE ANSWEER IS A>6x+16=49>2

Step-by-step explanation:

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Farmer Jane picked 2,552 strawberries. She shared the strawberries among 9 bins. She wrote an equation to find the total number
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D.

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R is remainder and to have equal amounts in each bin she could not put them in one.

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The graph below shows the solution to which system of inequalities
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Air pressure may be represented as a function of height (in meters) above the
denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

P(h) =P_0e^{-0.00012h}

In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute P(h)=0.5P_o into the function:

0.5P_o=P_0e^{-0.00012h}

2. Finally, you must solve for h.

Remember the following property of logarithms:

ln(b)^a=a*ln(b)\\\\ln(e)=1

Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

7 0
3 years ago
Restless Leg Syndrome and Fibromyalgia
mixas84 [53]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

6 0
3 years ago
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