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VikaD [51]
3 years ago
6

Your mother bought a three-liter bottle of water. When she got home, she discovered a small leak in the bottom and asked you to

find a container to transfer the water into. All you could find were two half-gallon jugs. Will your containers hold all of the water
Mathematics
2 answers:
Aleks [24]3 years ago
5 0
No it will not because if you put the two half gallons together, one gallon is equal to 3.785411784 liters
lord [1]3 years ago
4 0

Answer:

The two half-gallon jugs will hold all of the water.

Step-by-step explanation:

The gallon and the liter are two units of volume. Let's write the equivalent expression between them :

1gal=3.78541L

To solve this problem, we need to find out which volume is greater : The volume of the three-liter bottle or the volume of the two half-gallon jugs.

The volume of two half-gallon jugs is equal to :

Volume=(2).(\frac{1}{2})gal=1gal

Two half-gallon jugs can storage 1 gallon in total.

1 gal is equal to 3.78541 L (We write this at the beginning of the answer). Now, given that the volume of water stored by the three-liter bottle is 3 L or less (because of the small leak) :

3.78541L>3L

Therefore, the volume of the two containers is greater than the maximum volume of water stored in the three-liter bottle ⇒ The containers will hold all of the water.

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What kind of sequence has a common ratio
Makovka662 [10]

Answer:

geometric sequence

Step-by-step explanation:

A geometric sequence is a sequence of numbers that is ordered with a specific pattern. Each successive number is the product of the previous number and a constant. The constant is the same for every term in the sequence and is called the common ratio.

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3 years ago
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MrMuchimi

Answer:x=2; second option

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Raquel has created a program for a robot. The robot travels 10 meters and stops. The program is designed for wheels that are 2.5
Grace [21]

Answer:

Raquel should adjust the number of rotations  to 115.81 rotations

Step-by-step explanation:

step 1

Find the circumference of the wheels that are 2.5 cm in diameter

The circumference is equal to

C=2\pi r

we have

r=2.5/2=1.25\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.25)

C=7.85\ cm

step 2

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/7.85=127.39\ rotations

step 3

For a diameter of 2.75 cm find how should she adjust the number of rotations so that the robot travels the same distance

Find the circumference of the wheels

The circumference is equal to

C=2\pi r

we have

r=2.75/2=1.375\ cm

assume

\pi =3.14

substitute

C=2(3.14) (1.375)

C=8.635\ cm

step 4

Find the number of rotations

Divide 10 meters by the circumference

10\ m=1,000\ cm

1,000/8.635=115.81\ rotations

3 0
3 years ago
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