We are given the expression of the equation of a circle that is x2 + y2 + 14x + 2y + 14 = 0. Using ocmpleting the squares:
x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal ot square root of 36 equal to 6.
Answer:
I think the answer is y = 3x + 12.
Step-by-step explanation:
y = 3 (x - 1) (x - 4)
y = 3x -3 (x - 4)
y = 3x + 12
Answer:
C
Step-by-step explanation:
We can use process of elimination
D is incorrect because the roots are 3 and -4 and there are no negative roots visible
B is wrong because the roots -3 and -6 are both negative
You can factor A into (x-2)(x-3) and the roots are 2 and 3 but the roots on the graph look closer to 3 and 6
For C it can be factored as (x-6)(x-3) so the roots are 3 and 6 which look accurate