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Korolek [52]
3 years ago
5

1. estamate the sum

Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0

Step-by-step explanation:

1. \frac{11}{15}+\frac{1}{8}

\frac{11}{15}=0.733

\frac{1}{8}=0.125\approx 0

\frac{11}{15}+\frac{1}{8}=0.733+0.125\approx 1

The estimated sum is 1.

2. \frac{3}{4} \times 7\frac{2}{17}

\frac{3}{4}=0.75

7\frac{2}{17}=\frac{121}{17}=7.1176

\frac{3}{4} \times 7\frac{2}{17}=0.75\times 7.1176=5.3382\approx 5

3. \frac{5}{6} + \frac{4}{9}

\frac{5\times 9+4\times 6}{6\times 9}

\frac{69}{54}=\frac{23}{18}

\frac{5}{6} + \frac{4}{9}=\frac{23}{18}

podryga [215]3 years ago
5 0

Answer:

The sum for 11/15 + 1/8 = 103/120

The product for 4 3/4 * 7 2/17 = 33 55/68

The sum for 5/6 + 4/9 = 1 5/18

Hope that helps :)

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The primary purpose of the passage is to
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2 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

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Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

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