Answer:
Wyzant
ALGEBRA WORD PROBLEM
Dorian S. asked • 06/28/17
THREE LINEAR EQUATIONS WITH THREE VARIABLES
A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25%,
and the third contains 70%. He wants to use all three solutions to obtain a mixture of 40 liters containing 45%
acid, using 2 times as much of the 70% solution as the 25% solution. How many liters of each solution should be used?
How to set up as three linear equations to find the answer?
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Arthur D. answered • 06/28/17
TUTOR 4.9 (67)
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set up 2 equations
the first equation...
15%*x+25%*y+70%*2y=45%*40
0.15x+0.25y+1.4y=0.45*40
0.15x+1.65y=18
multiply all terms by 100
15x+165y=1800
divide all terms by 15
x+11y=120
the second equation...
x+y+2y=40
x+3y=40
x=40-3y
substitute into the first equation x+11y=120
40-3y+11y=120
40+8y=120
8y=120-40
8y=80
y=80/8
y=10 liters
x+3*10=40
x+30=40
x=40-30
x=10 liters
10 liters of 15%, 10 liters of 25%, and 20 liters of 70%
check:
10*15%=1.5
10*25%=2.5
20*70%=14
1.5+2.5+14=18
18/40=9/20=45/100=45%
45%*40=18
hope it helps
please mark brainliest
Answer:
The mean is 70, that's all I know. Sorry!
Step-by-step explanation:
Here's how you find the mean:
1. Add together ALL NUMBERS. (which equals 560 in this case.)
2. DIVIDE by the amount of numbers there are. (So 560 ÷ 8 = 70)
3. There's your answer! The mean of these numbers is 70.
I really hope this helps! Have a great day\night!
The value of m to 2
But I’m not completely sure
Well the GCF is the number that can be used to simplify, or that fits in all of your numbers for example this are all small numbers so 2 should fit in all of them 2 fits in 4 two times 2 fits in 2 one time and 2 fits in 6 three times now lets check our variable, to find the GCF of the variable first chekc if they all have the same if they don't u can't get none of taht variebles out, but if they repeat in all like the a u will take out the smallest amount out, for example the a as one in the degree of 1 the other in to the 2 degree and the last one to teh 3 degree well the smallest degree will be 1 so u will only take 1 a out so now ur GCF looks like 2a... Lets check the other variables, b is used in all of them and the smallest degree is b2 so we will take out 2 b's out so now my GCF looks like 2ab2 now lets check our last variable the, the c has the smallest degree of 1 so we will only take 1 c out
this means our final GCF is "2ab2c"
Hoep this helps
Possibly d, but I’m not sure, hope this helps ;)