
is differentiable across its domain, so the MVT says there is some value of

in the open interval

such that

You have

so the equation above becomes

Solve for

.




so

is indeed the average of the endpoints, i.e. the midpoint.
I thinks it’s c but cover your name so people don’t see it
Answer: 285
Step-by-step explanation:
302 - 20 + 3