The angle of depression the cable forms is the arctan of the ratio of the
horizontal distance to the height of the tower which is approximately 35°.
Response:
B. 35°
<h3>Which method can be used to find the angle of depression?</h3>
Given:
Height of the tower = 500-feet
Horizontal distance from the (other) point of attachment of the cable to
the base of the tower = 350-feet.
Required:
The angle of depression formed by the cable.
Solution:
The angle of depression is the angle, θ, the cable forms with the tower
from the top of the tower.
By trigonometric ratios, therefore;
Which gives;
The best correct option is; <u>B. 35°</u>
Learn more about trigonometric ratios here:
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9514 1404 393
Answer:
-1
Step-by-step explanation:
Your calculator can help with this.
24 -5² = 24 - 5·5 = 24 -25 = -1
Answer:
C)-2(9+32n)
Step-by-step explanation:
The given expresion is
We can rewrite this expression as:
We factor -2 to obtain:
Note that, we can use the distributive property to obtain:
Therefore the correct answer is C)-2(9+32n)
Answer:
The answer is (a) ⇒ x = 3.5
Step-by-step explanation:
In ΔABZ use the sin rule to find ∠ABZ and ∠BAZ
∵ AB/sin50° = AZ/sin∠ABZ
∴ 8.8/sin50° = 4.79/sin∠ABZ
∴ sin∠ABZ = (4.79 × sin50) ÷ 8.8
∴ sin ABZ = 0.416971
∴m∠ABZ = 24.64°
∴ m∠BAZ = 180 - (50 + 24.64) = 105.36°
In ΔABZ use the cosine rule to find BZ
(BZ)² = (BA)² + (AZ)² - 2(BA)(AZ)cos∠BAZ
∵ (BZ)² = (8.8)² + (4.79)² - 2(8.8)(4.79)cos105.36°
∴ (BZ)² = 122.7147953
∴ BZ = 11.078
Use the cosine rule in ΔCBZ to find CZ
(CZ)²= (BC)² + (BZ)² - 2(BC)(BZ)cos∠B
∵ (CZ)² = (4.79)² + (11.078)² - 2(4.79)(11.078)cos39²
∴ (CZ)² = 63.18982803
∴ CZ = 7.949
∵ CZ = 2x + 1
∴ 2x + 1 = 7.949
∴ 2x = 7.949 - 1 = 6.949
∴ x = 6.949 ÷ 2 = 3.47 ≅ 3.5
We will be using PEMDAS rule here :
P
- Parentheses first
E
- Exponents (ie Powers and Square Roots, etc.)
MD
- Multiplication and Division (left-to-right)
AS
- Addition and Subtraction (left-to-right)
8+2(12-5)
Step 1:
Solving parenthesis first:
8+2(7)
Step 2:
Multiplying 2*7
8+14
Step 3:
Adding 8 and 14
22
Answer is 22
