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Annette [7]
3 years ago
7

A prisoner on trial for a felony is presumed innocent until proven guilty. (That is, innocent is the null hypothesis.) Which of

the following represents the risk involved in making a Type II error?
a. The prisoner is actually guilty and the jury sends him to jail.

b. The prisoner is actually innocent and the jury sends him to jail.

c. The prisoner is actually innocent and the jury sets him free.

d. The prisoner is actually guilty and the jury sets him free.

e. The prisoner is sent to jail.
Mathematics
1 answer:
netineya [11]3 years ago
4 0

Answer:

Option D) The prisoner is actually guilty and the jury sets him free.

Step-by-step explanation:

We are given the following in the question:

Null Hypothesis:

The null hypothesis states that the prisoner is innocent

Alternate Hypothesis:

The alternate hypothesis states that the prisoner is guilty and not innocent.

Type II error:

It is the type error made when we fail to reject the ll hypothesis when it is actually false.

That is we accept a false null hypothesis.

Thus a type II error in the above scenario will be to accept that the prisoner is innocent (accepting the null hypothesis) when actually he is guilty( the alternate hypothesis)

Thus, type II error would be setting free a guilty prisoner.

Option D) The prisoner is actually guilty and the jury sets him free.

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nikitadnepr [17]

Answer:

option D is correct

Step-by-step explanation:

Hope it helps you

3 0
3 years ago
if you were to solve the following system by substitution what would be the best variable to solve and from what equation? 2x+8y
Nina [5.8K]
All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y

My choice would be to solve for x using the first equation.

_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35

4 0
3 years ago
An oil rig has a height of 74.98 m visible above water and extends 518.16 m below the surface to the sea floor. What is the tota
pashok25 [27]

Answer:

  1. So you know that the height that is visible above x=0 is 74.98 m
  2. From x=0 below it has a total height of 518.16m to the sea floor

That tells us that we have two parts account for

  1. 74.98+518.16m = 593.14 m
8 0
2 years ago
Read 2 more answers
Find sin θ if θ is in Quadrant III and tan θ = . 0.958
Leokris [45]
Use the following identities:
sec^2 = 1  + tan^2 \\  \\ sec = \frac{1}{cos} \\  \\ sin^2 = 1 - cos^2
Also because the angle is in quadrant 3, sin must be negative.
Therefore
sin = - \sqrt{1 - \frac{1}{1 + tan^2}}
Subbing in tan = 0.958
sin \theta = -0.69178
7 0
2 years ago
Solve for m: -13 =5(1+4m)-2m
erastovalidia [21]

Answer:


Step-by-step explanation:


-13 = 5(1+4m)-2m

-13=5+20m-2m

-13=5+18m

-13-5=18m

(-13-5)/18=m


6 0
3 years ago
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