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Annette [7]
3 years ago
7

A prisoner on trial for a felony is presumed innocent until proven guilty. (That is, innocent is the null hypothesis.) Which of

the following represents the risk involved in making a Type II error?
a. The prisoner is actually guilty and the jury sends him to jail.

b. The prisoner is actually innocent and the jury sends him to jail.

c. The prisoner is actually innocent and the jury sets him free.

d. The prisoner is actually guilty and the jury sets him free.

e. The prisoner is sent to jail.
Mathematics
1 answer:
netineya [11]3 years ago
4 0

Answer:

Option D) The prisoner is actually guilty and the jury sets him free.

Step-by-step explanation:

We are given the following in the question:

Null Hypothesis:

The null hypothesis states that the prisoner is innocent

Alternate Hypothesis:

The alternate hypothesis states that the prisoner is guilty and not innocent.

Type II error:

It is the type error made when we fail to reject the ll hypothesis when it is actually false.

That is we accept a false null hypothesis.

Thus a type II error in the above scenario will be to accept that the prisoner is innocent (accepting the null hypothesis) when actually he is guilty( the alternate hypothesis)

Thus, type II error would be setting free a guilty prisoner.

Option D) The prisoner is actually guilty and the jury sets him free.

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The ice cream man just ended his shift for the day. Let 1/2x^2 6/11x + 8 represent the amount of chocolate ice cream bars he sol
saveliy_v [14]

Answer:

A and D

Step-by-step explanation:

Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.

=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)

=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)

Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]

= (1/6)x2 - (38/11)x +(20/3)

So, the correct options are A and D

4 0
3 years ago
Let A = Andrea's age, Find expressions for the following
Shalnov [3]

Answer:

b = 2a - 2

Step-by-step explanation:

Turn the words into an algebraic expressions. so Andrea's (b)  is (=) two years less (-2) than (flips the expression so place this first ->) twice (times 2) her age (a) So b = 2a -2

5 0
3 years ago
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

3 0
2 years ago
The sum of two factors of 48 is nineteen. the larger factor, x, is one more than five times the smaller factor, y. which system
Ymorist [56]
Umm b. X = 19 + y I think because it has a add
5 0
3 years ago
Read 2 more answers
A conical vessels with base radius 5 cm and height 24cm is full of water this water is emptied into a cylindrical vessel of base
Aliun [14]

Answer:

2\ cm

Step-by-step explanation:

We\ are\ given\ that,\\Radius\ of\ the\ conical\ vessel=5\ cm\\Height\ of\ the\ conical\ vessel=24\ cm\\Hence,\\As\ we\ know\ that,\\Volume\ of\ a\ cone=\frac{1}{3}\pi r^2h\\Hence,\\The\ volume\ of\ the\ conical\ vessel=\frac{1}{3}\pi (5)^224=  \frac{1}{3}\pi 25*24=200\pi \\Hence,\\The\ volume\ of\ the\ conical\ vessel=The\ amount\ of\ water\ filled\ in\ it\\Hence,\\The\ amount\ of\ water\ filled\ in\ the\ conical\ vessel=200\pi\\Lets\ consider\ the\ cylindrical\ vessel:\\Volume\ of\ a\ cylinder=\pi r^2h

As\ we\ are\ not\ said\ that\ the\ cylindrical\ vessel\ was\ empty,\ let\ its\ initial\\ height\ be\ h_1\\Radius\ of\ the\ Cylindrical\ vessel=10\ cm\\Initial\ height\ of\ the\ cylindrical\ vessel=h_1\\Initial\ volume\ of\ the\ cylindrical\ vessel=\pi *10^2*h_1=100h_1\pi \\Initial\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi \\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=Final\ amount\ of\ water\\ in\ the\ cylindrical\ vessel +Amount\ of\ water\ in\ conical\ vessel

Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=100h_1\pi +200\pi \\Now,\\Let\ the\ final\ height\ be\ h_2\\Hence,\\Final\ amount\ of\ water\ in\ the\ cylindrical\ vessel=\pi *10^2*h_2=100h_2\pi \\Hence,\\100h_2\pi =100h_1\pi +200\pi \\Hence,\\100h_2=100h_1+200\\100h_2-100h_1=200\\100(h_2-h_1)=200\\h_2-h_1=2\\Hence,\\As\ the\ rise\ in\ level\ is\ the\ difference\ between\ the\ initial\ and\ final\\ heights:\\The\ rise\ in\ level\ of\ water=2\ cm

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