Answer:
65.2 %
Explanation:
Let Q1 = Heat absorbed by the system
Q2 = Heat released by the system
e= (1 - (Q2/Q1)) x 100
e= (1 - (750/2150)) x 100
e= (1 - 0.348) x 100
e= 0.652 x 100
e= 65.2 %
Λ
![= 550 * 10^{-9}\] m. D = 3.50*10^-6 m.](https://tex.z-dn.net/?f=%20%3D%20550%20%2A%2010%5E%7B-9%7D%5C%5D%20m.%0A%0AD%20%3D%203.50%2A10%5E-6%20m.)

Then you need to find x when n=1
or

≈θ for θ<<1 , so θ=

Then you can find rhe distance of<span> bright fringe from the center:</span>
Answer:
3.53*10^{-7} m
Explanation:
Photon that can rupture the bonds are those with the energy of the bond dissociation energy. If we want to know the energy for each molecule we have to take into account that:

Hence, we have

but the energy is also:

where h is the Planck's constant and c is the speed of ligth. By replacing we obtain:

hope this helps!
Answer:
Explanation:
Initially the two boys were sitting on the periphery , total moment of inertia
= 1/2 M r² + 2mr² ; M is mass of the merry go round , m is mass of each boy and r is the radius
1/2 x 200 x 2² + 2 x 40 x 2²
= 400 + 320
I₁ = 720 kg m²
Finally the two boys were sitting at the middle , total moment of inertia
= 1/2 M r² + 2m( r/2)² ; M is mass of the merry go round , m is mass of each boy and r is the radius
1/2 x 200 x 2² + 2 x 40 x 1²
= 400 + 80
I₂ = 480
Now the system will obey law of coservation of angular momentum because no torque is acting on the system.
I₁ω₁ = I₂ω₂ , I₁ and ω₁ are moment of inertia and angular velocity of first case and I₂ and ω₂ are of second case.
720 X 12 = 480 ω₂
ω₂ = 18 rad / s