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4 years ago

A story problem for 388 + 235

Mathematics

2 answers:

Anvisha [2.4K]4 years ago

8 0

I had 388 pencils and Sally gave me 235 how many do I have now

kherson [118]4 years ago

7 0

My friend James and his fiance, Mary are planning a wedding. After months of planning and cutting down on people on their guest list, they have finalized all the invites. Mary has 388 people that she wants to invite and James has 235 people he wants to invite. How many people do they want to invite all together?

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ANSWER FOR BRAINLIEST:

Feliz [49]

B because the center of data is best measured by the median when there are outliers, and 42 is an outlier in this set.

5 0

3 years ago

-7.5x + 0.25 = -5.75 The value of x is =

VashaNatasha [74]

Answer:

x = 4/5

I hope this helps!

3 0

3 years ago

Read 2 more answers

Jerry has been learning to multiply decimals by Integers.

Bogdan [553]

Answer:

Yes

Step-by-step explanation:

Multiplying an integer by 0.01 is the same as Dividing such as :

0.01 = 10^-2

100= 10

For instance :

A number, n = 5 is multiplied by 10^-2

5 * 0.01 = 0.05

Thus, divide the number, n by 100;

5 / 100 = 0.05

Hence, the proof.

7 0

3 years ago

14.4% of what number is 10.4

Helga [31]

First, convert "of" to x and put this info into an equation:

Let n represent the unknown number.

14.4 % x n= 10.4
n = 10.4 / 14.4%
n = 72.22222
n = ~72

Hope this helps!

8 0

4 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

4 years ago