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labwork [276]
3 years ago
5

An investment is currently worth 1.2×107 dollars . Twenty years ago, the investment was worth ​ 9.6×105 ​ dollars. How many time

s greater is the value of the investment today than the value of the investment twenty years ago? 0.125 12.5 125 12,500
Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

Answer:

12.5

Step-by-step explanation:

Let an old value be A

and a new value be B

Also, let B is greater than A

The number of times B is greater than A is found by dividing B by A

Now, in terms of scientific notation, how would we do the division? It is shown below:

\frac{a*10^b}{z*10^y}=(\frac{a}{z})*10^{b-y}

Now, coming to our question, let's do the math using the statements and formulas we have seen above:

\frac{1.2*10^7}{9.6*10^5}\\=(\frac{1.2}{9.6})*10^{7-5}\\=0.125*10^2

10^2 means 100, so we do the multiplication:

0.125*10^2\\0.125*100\\12.5

So, it is 12.5 times greater

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3 years ago
What is the value of y in the triangle
Scrat [10]

Answer:

y ≈ 6.7

Step-by-step explanation:

Using the sine ratio in the right triangle

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15 × sin26.5° = y , then

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5 0
3 years ago
Maria is ordering copy paper for her office. The office is low on white paper and on blue paper. She will pay $3.50 per realm of
maxonik [38]
You have:

 x: the number of reams of white paper purchased 
 y:the number of reams of blue paper purchased 

 Then, you have the following system of equations:

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 The answer is: 6 reams of white paper
 
8 0
3 years ago
Read 2 more answers
the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?
olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= \frac{-3y}{y-1}

Similarly fourth term will be

x-3y-2y=x-5y

x-5y=\frac{x}{y}

substitute the value of x  in the equation

\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0

Split the middle term and factorize it

5y^{2}+3y-5y-3=0\\y(5y+3)-1(5y+3)=0\\

(y-1)(5y+3)=0

y=1,\frac{-3}{5}

y cannot be equal to 1, because the third term and fourth term will become x.

y=\frac{-3}{5}

substitute the value of y in the equation of x
x=\frac{-3y}{y-1} \\=\frac{-3\frac{-3}{5} }{\frac{-3}{5}-1 }\\ =\frac{-9}{8}

The fifth term= \frac{x}{y}+(-2y)=\frac{x}{y} -2y

\frac{\frac{-9}{8} }{\frac{-3}{5} }-2\frac{-3}{5}  =\frac{123}{40}

Hence, when the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

Learn more about Arithmetic sequence here

brainly.com/question/15412619

#SPJ4

5 0
2 years ago
1. What is the slope of the line that passes through the points (-1, -11) and (-6, -7)?​
vfiekz [6]

Answer:

The slope of the line is -4/5 or -0.8

Step-by-step explanation:

Slope =  \frac{rise}{run} =\frac{y_{2} -y_{1}}{x_{2}-x_{1}} =\frac{(-7)-(-11)}{(-6)-(-1)} =\frac{4}{-5} =\frac{-4}{5} =-0.8

6 0
3 years ago
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