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kirill115 [55]
3 years ago
7

When Amy turns on her computer, she notices a burning smell. Smoke comes out of the case, and Amy immediately turns off her comp

uter. What might be causing Amy’s computer to emit smoke and a burning smell?
Computers and Technology
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

"Power Problem" is the correct answer for the given question .

Explanation:

When Amy starts the computer she feels the smell of burning because there is power problem in her switches which makes the burning of wires. The power problem may arise be due to the failure of Fan which is inside the central processing unit Another reason for power Failure may be the fluctuation of the voltage due to this it makes the overheating of the power supply.

When Amy saw this problem it immediately shut down the computer to protect her computer.

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State three positive uses of the computer in the government sector​
WINSTONCH [101]

Well Here I got 4

1. Email Functions

2. Distributing Payments

3. Record Keeping

4. Direct Mail Promotions

<em>Have A great night!</em>

<em></em>

6 0
3 years ago
can I do all my work in a notebook with Penn foster or do I have to type all of the answers in that little box?
dusya [7]
Um whichever is better for you! ummm whats the point of this question?
5 0
3 years ago
Read 2 more answers
A class member function that automatically initializes the data members of a class is called?
____ [38]

A class member function that automatically initializes the data members of a class exists called a constructor.

<h3>What is meant by member function?</h3>

Operators and functions that are designated as members of a class are known as member functions. Operators and functions declared with the friend specifier are not included in member functions. These are referred to as class pals. Together, data members and member functions describe the characteristics and actions of the objects in a Class. Data members are the data variables, and member functions are the functions used to control these variables.

In C++, there are typically five different types of member functions available. Specifically, friend member functions and basic, static, const, inline functions. Classes-only functions are member functions. Any private, protected, or public member of its class may be accessed using the public member function. Any member function of a class, not just the public ones, has access to every single other member that has been declared inside the class. so are easy to programme.

Hence, A class member function that automatically initializes the data members of a class exists called a constructor.

To learn more about member functions refer to:

brainly.com/question/15554910

#SPJ4

3 0
1 year ago
Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less
nataly862011 [7]

Complete Question:

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with a newline. Ex: For the user input 123, 395, 25, the expected output is:

Enter a number (<100):

Enter a number (<100):

Enter a number (<100):

Your number < 100 is: 25

Answer:

import java.util.Scanner;

public class num8 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int n;

       do{

           System.out.println("Enter a number (<100):");

           n= in.nextInt();

       }while(n>100);

       System.out.println("Your number < 100 is: "+n);

   }

}

Explanation:

Using Java programming language

Import the scanner class to receive user input

create an int variable (n) to hold the entered value

create a do while loop that continuously prompts the user to enter a number less than 100

the condition is while(n>100) It should continue the loop (prompting the user) until a number less than 100 is entered.

4 0
2 years ago
Read 2 more answers
There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou
Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:-  n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex  u ∈ V

\rightarrow  for each vertex v ∈ V

\rightarrow\rightarrowif( d(pu, pj) > k )

\rightarrow\rightarrow\rightarrow add vertex u to Adj[v]   // Adj[v] represents adjacency list of v

\rightarrow\rightarrow\rightarrow add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3.  bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

\rightarrowvisited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph  

6. for each vertex u ∈ V  

\rightarrow if ( visited[u] == false)

\rightarrow\rightarrow color[u] = 0;

\rightarrow\rightarrow isbipartite = BFS(G,u,color,visited)  // if the vertices reachable from u form a bipartite graph, it returns true

\rightarrow\rightarrow if (isbipartite == false)

\rightarrow\rightarrow\rightarrow print " No solution exists "

\rightarrow\rightarrow\rightarrow exit(0)

7.  for each vertex u ∈V

\rightarrow if (color[u] == 0 )

\rightarrow\rightarrow print " Student u is assigned Bus 1"

\rightarrowelse

\rightarrow\rightarrow print " Student v is assigned Bus 2"

BFS(G,s,color,visited)  

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

\rightarrow u = Q.pop()

\rightarrow for each vertex v ∈ Adj[u]

\rightarrow\rightarrow if (visited[v] == false)

\rightarrow\rightarrow\rightarrow color[v] = (color[u] + 1) % 2

\rightarrow\rightarrow\rightarrow visited[v] = true

\rightarrow\rightarrow\rightarrow Q.push(v)

\rightarrow\rightarrow else

\rightarrow\rightarrow\rightarrow if (color[u] == color[v])

\rightarrow\rightarrow\rightarrow\rightarrow return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0
3 years ago
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