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dimulka [17.4K]
3 years ago
10

Factor the expression completely -9.75 + 3.25x

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0
3.25*(x-3)

Just take out a 3.25
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Write this number in word form 3,388,198
Minchanka [31]

Three million three hundred eighty eight  thousand one hundred ninety eight.

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3 years ago
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Mr. Walker asked his students to use the associative property to find an expression that is equivalent to (13 + 15 + 20) + (20 +
pychu [463]
I got it as 4 when calculating all have the same number which is 133
7 0
3 years ago
What is the circumference, in centimeters, of the circle? Use 3.14 for π. Enter your answer in the box. (the diameter is 24cm)
gizmo_the_mogwai [7]

The circumference of the circle is 75.36 cm.

  • Step 1: Given data:

Diameter of the circle is 24 cm,

\pi = 3.14

  • Step 2: Formula used and calculation:

Circumference of the circle is 2\pi r.

So, Radius, r = 24/2 = 12 cm.

Now, Putting the value in the above formula, we get

2 × 3.14 ×12 = 3.14 × 24 = 75.36 cm.

Hence, the circumference of the circle is 75.36 cm.

Learn more about circumference of the circle, refer:

brainly.com/question/23964435

8 0
2 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
Helppppppp fastttttttttttttttttttt
ryzh [129]

Answer:

4

Step-by-step explanation:

12/2 = 6

24/6 = 4

4 0
2 years ago
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