How do you find the length of the legs when only given the hypotenuse with an isosceles right triangle?
1 answer:
The side length ratios of an isosceles right triangle are 1-1-
. So, the length of a leg would be equal to the length of the hypotenuse divided by the square root of 2.
Using pythagorean theorem (c is the hypotenuse, a and b are the legs)
c²=a²+b²
If the triangle is isosceles, two side lengths must be equal. In the case of a right triangle, the legs must be equal in length. So, b=a.
c²=a²+a²
c²=2a²
a²=c²/2
a=c/
a≈c/1.414
Using pythagorean theorem (c is the hypotenuse, a and b are the legs)
c²=a²+b²
If the triangle is isosceles, two side lengths must be equal. In the case of a right triangle, the legs must be equal in length. So, b=a.
c²=a²+a²
c²=2a²
a²=c²/2
a=c/
a≈c/1.414
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Answer:
Initial velocity is zero.
Step-by-step explanation:
According to second equation of motion
where s = distance traveled
t = time taken
a = acceleration
u = initial velocity
here in the question we have
s = 10 m
t = 1 second
a = 20
plugging the known value in order to find the unknown which is u (initial velocity)
[tex]10=u(1)+\frac{1}{2} (20)(1)^2[/tex
10 = u +10
gives u =0
therefore initial velocity is zero.