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Lemur [1.5K]
3 years ago
10

Anyone know how to solve this?​

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer: n = 8 or n= 12

Step-by-step explanation:

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Find the volume of a sphere with a great circle area of 201.06 square inches
Vikentia [17]
Assuming you meant a "circular cross-section" of 201.06 in².

so, we know if we cut the sphere like a cantaloupe, in half, the circular inner-part of the cantaloupe will have an area of 201.6 in².

keeping in mind that, the radius of that circular section, is the same radius of the sphere, what is it anyway?

\bf \textit{area of a circle}\\\\
A=\pi r^2~~
\begin{cases}
r=radius\\
-----\\
A=201.06
\end{cases}\implies 201.06=\pi r^2
\\\\\\
\cfrac{201.06}{\pi }=r^2\implies \sqrt{\cfrac{201.06}{\pi }}=r\\\\
-------------------------------

\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad \qquad \implies V=\cfrac{4\pi \left( \sqrt{\frac{201.06}{\pi }} \right)^3}{3}\implies V=\cfrac{4\pi \left( \frac{\sqrt{201.06^3}}{\sqrt{\pi ^3}} \right)}{3}
\\\\\\
V=\cfrac{4\pi \cdot \frac{\sqrt{201.06^3}}{\pi \sqrt{\pi }}}{3}\implies V=\cfrac{\frac{4\sqrt{201.06^3}}{\sqrt{\pi }}}{3}\implies V=\cfrac{4\sqrt{201.06^3}}{3\sqrt{\pi }}
6 0
3 years ago
Amira has \dfrac34 4 3 ​ start fraction, 3, divided by, 4, end fraction of a bag of cat food. Her cat eats \dfrac{1}{10} 10 1 ​
irakobra [83]

Answer:

  7.5 weeks

Step-by-step explanation:

Divide the amount by the rate to find the time:

  (3/4 bag)/(1/10 bag/week) = 30/4 week = 7.5 weeks

3 0
3 years ago
Read 2 more answers
X+140=300 solve the equation and check your solution ​
julsineya [31]

Answer:

x=300-140

x=160

Step-by-step explanation:

hope it help you

8 0
2 years ago
Find the surface area of a cylindrical can that is 6 inches tall and has a diameter of 4 inches, use π ( pi ) = 3.14
cricket20 [7]

Answer:

C

Step-by-step explanation:

Radius = 4/2 = 2 in

SA = 2pi×r×h + 2pi×r²

= (2×3.14×2×6) + (2×3.14×2²)

= 100.48 in²

8 0
3 years ago
b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and
rjkz [21]

Answer:

<em>99% of confidence intervals for mean age of ICU patients</em>

<em>(53.8920 , 61.2079)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given sample mean </em>x^{-} = 57.55<em></em>

Given standard error is determined by

                                                             S.E =\frac{S.D}{\sqrt{n} }

<em>Given data standard error = 1.42</em>

<em>99% of confidence intervals for mean is determined by</em>

(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} } )

Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.05} = 2.576

(x^{-} - 2.576 S.E , x^{-} + 2.576 S.E)

(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)

(53.8920 , 61.2079)

<u><em>Conclusion</em></u>:-

<em>99% of confidence intervals for mean is determined by</em>

<em>(53.8920 , 61.2079)</em>

5 0
3 years ago
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