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3 years ago

The slope field for the differential equation dy/dx=(3y)/(xy+5x) will have vertical segments when

Mathematics

1 answer:

Inessa05 [86]3 years ago

3 0

Answer:

E) x=0 or y=-5

Step-by-step explanation:

The slope field will have vertical segments when dy/dx is undefined, that is, dy/dx is a division by 0.

We have that

dy/dx=(3y)/(xy+5x)

So the slope field will have vertical segments when

$xy + 5x = 0$

$x(y + 5) = 0$

This is when x = 0 or y = -5.

So the correct answer is:

E) x=0 or y=-5

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HELP ASAP!

sladkih [1.3K]

Hey there!!

Let's take the first number as ' x '

Then, the second number would be ' x + 1 '

Sum of these = 183

Hence,

$x + x + 1 = 183$

$2x + 1 = 183$

$2x = 182$

$x = \frac{182}{2}$

$x = 91$

Hence, the small integer is 91

Hope my answer helps!

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3 years ago

Find the perimeter of a rectangle with a width of (x - 3) and a length of 4x

Firdavs [7]

Step-by-step explanation:

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x-3| | x-3

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Add all sides together to get perimeter

2(4x)+2(x-3)=10x-6

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2 years ago

PLEASE HELP 100!!! POINTS

faust18 [17]

Answer:

Most Unlikely: Less than 5

Likely: 2-digit number

Unlikely: Multiple of 3

Equally Likely: Odd

Most Likely: Greater than 10

Step-by-step explanation:

there are 6x5, or 30 outcomes

Less than 5 has 1 outcome - spinner and dice both are one

Odd has 15 outcomes

Multiple of 3 has 8 outcomes: 1+5, 2+1, 2+7, 2+12, 3+12, 4+5, 5+7, 5+10

Two-digits has 12 outcomes

Greater than ten has 16 outcomes

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2 years ago

Solve the following differential equation using using characteristic equation using Laplace Transform i. ii y" +y sin 2t, y(0) 2

kifflom [539]

Answer:

The solution of the differential equation is $y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

Step-by-step explanation:

The differential equation is given by: y" + y = Sin(2t)

i) Using characteristic equation:

The characteristic equation method assumes that y(t)= $e^{rt}$ , where "r" is a constant.

We find the solution of the homogeneus differential equation:

y" + y = 0

$y'=re^{rt}$

$y"=r^{2}e^{rt}$

$r^{2}e^{rt}+e^{rt}=0$

$(r^{2}+1)e^{rt}=0$

As $e^{rt}$ could never be zero, the term (r²+1) must be zero:

(r²+1)=0

r=±i

The solution of the homogeneus differential equation is:

$y(t)_{h}=c_{1}e^{it}+c_{2}e^{-it}$

Using Euler's formula:

$y(t)_{h}=c_{1}[Sin(t)+iCos(t)]+c_{2}[Sin(t)-iCos(t)]$

$y(t)_{h}=(c_{1}+c_{2})Sin(t)+(c_{1}-c_{2})iCos(t)$

$y(t)_{h}=C_{1}Sin(t)+C_{2}Cos(t)$

The particular solution of the differential equation is given by:

$y(t)_{p}=ASin(2t)+BCos(2t)$

$y'(t)_{p}=2ACos(2t)-2BSin(2t)$

$y''(t)_{p}=-4ASin(2t)-4BCos(2t)$

So we use these derivatives in the differential equation:

$-4ASin(2t)-4BCos(2t)+ASin(2t)+BCos(2t)=Sin(2t)$

$-3ASin(2t)-3BCos(2t)=Sin(2t)$

As there is not a term for Cos(2t), B is equal to 0.

So the value A=-1/3

The solution is the sum of the particular function and the homogeneous function:

$y(t)= - \frac{1}{3} Sin(2t) + C_{1} Sin(t) + C_{2} Cos(t)$

Using the initial conditions we can check that C1=5/3 and C2=2

ii) Using Laplace Transform:

To solve the differential equation we use the Laplace transformation in both members:

ℒ[y" + y]=ℒ[Sin(2t)]

ℒ[y"]+ℒ[y]=ℒ[Sin(2t)]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]-s·y(0)-y'(0)=s²·Y(s) -2s-1

ℒ[y]=Y(s)

ℒ[Sin(2t)]= $\frac{2}{(s^{2}+4)}$

We replace the previous data in the equation:

s²·Y(s) -2s-1+Y(s) = $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)-2s-1= $\frac{2}{(s^{2}+4)}$

(s²+1)·Y(s)= $\frac{2}{(s^{2}+4)}+2s+1=\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)}$

Y(s)= $\frac{2+2s(s^{2}+4)+s^{2}+4}{(s^{2}+4)(s^{2}+1)}$

Y(s)= $\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}$

Using partial franction method:

$\frac{2s^{3}+s^{2}+8s+6}{(s^{2}+4)(s^{2}+1)}=\frac{As+B}{s^{2}+4} +\frac{Cs+D}{s^{2}+1}$

2s^{3}+s^{2}+8s+6=(As+B)(s²+1)+(Cs+D)(s²+4)

2s^{3}+s^{2}+8s+6=s³(A+C)+s²(B+D)+s(A+4C)+(B+4D)

We solve the equation system:

A+C=2

B+D=1

A+4C=8

B+4D=6

The solutions are:

A=0 ; B= -2/3 ; C=2 ; D=5/3

So,

Y(s)= $\frac{-\frac{2}{3} }{s^{2}+4} +\frac{2s+\frac{5}{3} }{s^{2}+1}$

Y(s)= $-\frac{1}{3} \frac{2}{s^{2}+4} +2\frac{s }{s^{2}+1}+\frac{5}{3}\frac{1}{s^{2}+1}$

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[ $-\frac{1}{3} \frac{2}{s^{2}+4}$ ]-ℒ⁻¹[ $2\frac{s }{s^{2}+1}$ ]+ℒ⁻¹[ $\frac{5}{3}\frac{1}{s^{2}+1}$ ]

$y(t)= - \frac{1}{3} Sin(2t)+2 Cos(t)+\frac{5}{3} Sin(t)$

3 0

3 years ago

Lola is saving money for a new bike. The first month, she saves $50 from her birthday. Lola plans to save $10 per month thereaft

weqwewe [10]

So this can be translated like the following:
Bike costs= 173 dollars She currently has 107. She saves 11 dollar per week to get the bike so the formula is:
173 = 107 + 11X where X is the number of weeks

Step 1: bring the 107 to the other side to get 173-107 = 11X
Step 2: divide both sides by 11 to solve for X to get this (173-107 )/11 = X
Step 3: Calculate and simplify 66 / 11 = X which is the same as X= 6

So the answer is it will take jennifier 6 weeks to save for the bike.

8 0

3 years ago