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3 years ago

Solve the simultaneous equation using substitution method x-y=8 and 4x+y=4

Mathematics

1 answer:

aleksklad [387]3 years ago

7 0

x - y = 8

Add y to both sides

x = 8 + y

4x + y = 4

Substitute the value of x from the first equation in

4(8 + y) + y = 4

Simplify and solve

32 + 4y + y = 4

32 + 5y = 4

5y = -28

y = -5.6

Now put that value of y into the first equation

x = 8 + (-5.6)

x = 2.4

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3 years ago

Read 2 more answers

Solve the question: 4/5 (b-1)-1/b=1

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3 years ago

Diego eats 1/5 of a loaf of bread each day. On Tuesday, Diego eats 1/4 of the day’s portion before lunch. What fraction of the w

LiRa [457]

Answer:

$\frac{1}{20}$

Step-by-step explanation:

We have been given that Diego eats 1/5 of a loaf of bread each day. On Tuesday, Diego eats 1/4 of the day’s portion before lunch.

To find the fraction of the whole loaf eaten by Diego before lunch on Tuesday, we will find 1/4 of 1/5 as:

$\text{Fraction of the whole loaf eaten by Diego}=\frac{1}{5}\times \frac{1}{4}$

$\text{Fraction of the whole loaf eaten by Diego}=\frac{1\times1}{5\times4}$

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Therefore, Diego has eaten $\frac{1}{20}$ of the whole loaf before lunch on Tuesday.

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3 years ago

Steph knows that two pens are about eight paper clips long. How can steph estimate the length of one pen

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Answer:

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Step-by-step explanation:

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4 years ago

A²,b²,c² are consecutive perfect squares.How many natura numbers are lying between a² and c², if a>0

pogonyaev

Answer:

The quantity of natural numbers between $a^{2}$ and $c^{2}$ is $2\cdot (a + b) + 1$ .

Step-by-step explanation:

If $a^{2}$ , $b^{2}$ and $c^{2}$ are consecutive perfect squares, then both $a$ , $b$ and $c$ are natural numbers and we have the following quantities of natural numbers:

Between $b^{2}$ and $c^{2}$ :

$c^{2} = (b+1)^{2}$

$c^{2} = b^{2}+2\cdot b + 1$

$c^{2}-b^{2} = 2\cdot b + 1$

And the quantity of natural numbers between $b^{2}$ and $c^{2}$ is:

$c^{2}-b^{2}-1 = 2\cdot b$

Between $a^{2}$ and $b^{2}$ :

$b^{2} = (a + 1)^{2}$

$b^{2} = a^{2} +2\cdot a + 1$

$b^{2}-a^{2} = 2\cdot a + 1$

And the quantity of natural numbers between $a^{2}$ and $b^{2}$ is:

$b^{2}-a^{2}-1 = 2\cdot a$

And the quantity of natural numbers between $a^{2}$ and $c^{2}$ is:

$Diff = 2\cdot a + 2\cdot b + 1$

Please observe that the component +1 represents the natural number $b^{2}$

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3 years ago

Solve the simultaneous equation using substitution method x-y=8 and 4x+y=4​

Solve the simultaneous equation using substitution method x-y=8 and 4x+y=4