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mr Goodwill [35]
3 years ago
13

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0
Hello,

Answer B: y-axis only
==================


prisoha [69]3 years ago
5 0

Answer:

<h2>y-axis only.</h2>

Step-by-step explanation:

The given equation is

r=2+3sin \theta

Notice that this equation is in polar form.

If (r, \theta) can be replace with (r, \pi - \theta) or (-r, -\theta), then the graph is symmetric to the line \theta = \frac{\pi}{2}, which is a vertical line.

Let's evaluate the given equation.

r=2+3sin \theta=2+3sin(\pi -\theta)= 2-3sin(- \theta)

But, sin(-\theta)=-sin \theta

So,  r= 2-3sin(- \theta)=2-(-3sin\theta)=2+3sin\theta=r

Notice that the change produces the same equation.

Therefore, the given polar expression is symmetric to \theta  = \frac{\pi}{2}, which is the y-axis only in the coordinate system.

So, the right answer is y-axis only.

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5c +2d=13<br> 2c + 4d = -6
Margarita [4]

Answer:

combine like terms and u'll have ur answer

Step-by-step explanation:

4 0
3 years ago
Please help with these problems! Will mark answer as brainliest and give 30 points. You have to show your work for each problem.
gulaghasi [49]

Answer:

1) (2x + 2)(x + 2)

2)  2(x + 1)(x - 1)

3) (x^2 + 3)(x^2 - 3)

4) 2x(x + 5)(x - 2)

5) (5x + 2y)(5x - 2y)

Step-by-step explanation:

1)

2x^2 + 6x + 4

= 2x^2 + 4x + 2x + 4

= 2x(x + 2) + 2(x + 2)

= (2x + 2)(x + 2)

2)

2x^2 - 2

= 2(x^ 2 - 1) (The difference of two squares)

= 2(x + 1)(x - 1)

3)

x^4 - 9 (The difference of two squares)

=(x^2 + 3)(x^2 - 3)

4)

2x^3 + 6x^2 - 20x

= 2x(x^2 + 3x - 10)

= 2x(x + 5)(x - 2)

5)

25x^2 - 4y^2         (The difference of two squares)

= (5x + 2y)(5x - 2y)

4 0
3 years ago
2. Think of the top and middle shelves as two lines cut by a transversal. What type of angles are
nadya68 [22]

Answer:

Angles 1 and 5 are corresponding angles.

Step-by-step explanation:

These are the different types of angles formed by a transversal:

1. Corresponding angles are angles that lie on the <em>same side</em> of the transversal line. Angles 1, 3, 5, 6, 9, and 11 are corresponding angles because they are all on the left side of the transversal (the line that cuts through the other lines). Angles 2, 4, 6, 8, 10, and 12 are corresponding angles because they are all on the right side of the transversal.

2. Alternate interior angles are angles that are nonadjacent angles that lie on opposite sides of the transversal and in between the horizontal lines. Here the alternate interior angles are 3 and 6, 4 and 5, 7 and 10, and 8 and 9.

3. Alternate exterior angles are those that are nonadjacent and lie on the outside of the horizontal lines. In this diagram, angles 1 and 12 and angles 2 and 11 are alternate exterior.

4. Same-side interior angles are angles that lie on the same side of the transversal and in between the horizontal lines. The same-side interior angles in this diagram are angles 3 and 5, 7 and 9, 4 and 6, and 8 and 10.

5 0
3 years ago
Given:quadrillateral ABCD inscribed in a circle
son4ous [18]

Answer:

Step-by-step explanation:

Given: quadrilateral ABCD inscribed in a circle

To Prove:

1. ∠A and ∠C are supplementary.

2. ∠B and ∠D are supplementary.

Construction : Join AC and BD.

Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,

∠1=∠2-----(1)

∠3=∠4-----(2)

∠5=∠6-------(3)

∠7=∠8------(4)

Also, sum of angles of quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°

→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4

→→→2∠1+2∠4+2∠6+2∠8=360°

→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,

→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)

As, ∠A+∠B+∠C+∠D=360°

∠A+∠C+180°=360°

∠A+∠C=360°-180°------Using A

∠A+∠C=180°

Hence proved.

credit: someone else

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3 years ago
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