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mr Goodwill [35]
2 years ago
13

Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

Mathematics
2 answers:
AfilCa [17]2 years ago
5 0
Hello,

Answer B: y-axis only
==================


prisoha [69]2 years ago
5 0

Answer:

<h2>y-axis only.</h2>

Step-by-step explanation:

The given equation is

r=2+3sin \theta

Notice that this equation is in polar form.

If (r, \theta) can be replace with (r, \pi - \theta) or (-r, -\theta), then the graph is symmetric to the line \theta = \frac{\pi}{2}, which is a vertical line.

Let's evaluate the given equation.

r=2+3sin \theta=2+3sin(\pi -\theta)= 2-3sin(- \theta)

But, sin(-\theta)=-sin \theta

So,  r= 2-3sin(- \theta)=2-(-3sin\theta)=2+3sin\theta=r

Notice that the change produces the same equation.

Therefore, the given polar expression is symmetric to \theta  = \frac{\pi}{2}, which is the y-axis only in the coordinate system.

So, the right answer is y-axis only.

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Answer:

# m∠A = 65.3°

# m∠A = 25.8°

# m∠A = 22.7°

Step-by-step explanation:

* Lets revise the trigonometry function to solve the problem

- In any right angle triangle:

# The side opposite to the right angle is called the hypotenuse

# The other two sides are called the legs of the right angle

* If the name of the triangle is ABC, where B is the right angle

∴ The hypotenuse is AC

∴ AB and BC are the legs of the right angle

- ∠A and ∠C are two acute angles

- For angle A

# sin(A) = opposite/hypotenuse

∵ The opposite to ∠A is BC

∵ The hypotenuse is AC

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# cos(A) = adjacent/hypotenuse

∵ The adjacent to ∠A is AB

∵ The hypotenuse is AC

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# tan(A) = opposite/adjacent

∵ The opposite to ∠A is BC

∵ The adjacent to ∠A is AB

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* Lets solve the problems

# In Δ ABC

∵ m∠B = 90°

∵ AB = 2.3 ⇒ adjacent to angle A

∵ BC = 5 ⇒ apposite to angle A

- To find m∠A use the tangent function because we have opposite

  and adjacent sides

∴ tan A = BC/AB

∴ tan A = 5/2.3 ⇒ use tan^-1 to find m∠A

∴ m∠A = tan^{-1}\frac{5}{2.3}=65.29756

* m∠A = 65.3°

# In Δ ABD

∵ m∠B = 90°

∵ AB = 5.4 ⇒ adjacent to angle A

∵ DA = 6 ⇒ the hypotenuse

- To find m∠A use the cosine function because we have adjacent

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∴ cos A = AB/DA

∴ cos A = 5.4/6 ⇒ use cos^-1 to find m∠A

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* m∠A = 25.8°

# In Δ ABE

∵ m∠B = 90°

∵ EB = 2.4 ⇒ opposite to angle A

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∴ sin A = EB/EA

∴ sin A = 2.4/6.8 ⇒ use sin^-1 to find m∠A

∴ m∠A = sin^{-1}\frac{2.4}{6.8}=22.6673

* m∠A = 22.7°

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