All categories

3 years ago

Out of 3 Cad-bury chocolates and 2 Kitkat bars, if one is picked at random, what is the probability that it will be a kitkat?

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

2/5

Step-by-step explanation:

3+2 = 5

2 kitkats, 5 total chocolates, 2/5

hope this helps.

kotykmax [81]3 years ago

4 0

Answer:

There would be a 20% probability. Since theres 5 bars in all, divide 100% by 5 and you get 20% for each bar. I hope this helped

You might be interested in

Item 5 Identify the terms, coefficients, and constants in the expression 6 + n x n + 1/2d

Alenkasestr [34]

Answer:

Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

Step-by-step explanation:

6 + n x n + 1/2d

6 + n^2 x + 1/2d

Terms (Variables) = x , d . Their corresponding coefficients = n^2 , 1/2 . Constant = 6

7 0

3 years ago

Answer...............

aev [14]

In the given graph point B is a relative maximum with the coordinates (0, 2).

The given function is $y=x^{4}-2x^{2} +1$ .

In the given graph, we need to find which point is a relative maximum.

<h3>What are relative maxima?</h3>

The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.

In the graph, the maximum point is (0, 2).

Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).

To learn more about the relative maximum visit:

brainly.com/question/2321623.

#SPJ1

8 0

2 years ago

X³ by a³ + a³by x³=p x³by a³- a³by ³=q eliminate x

sasho [114]

Answer:

Step-by-step explanation:

$\frac{x^3}{a^3} +\frac{a^3}{x^3} =p\\\frac{x^3}{a^3} -\frac{a^3}{x^3} =q\\adding\\2\frac{x^3}{a^3} =p+q\\\frac{x^3}{a^3} =\frac{p+q}{2} \\substitute~in~first\\\frac{p+q}{2} +\frac{2}{p+q} =p\\\frac{(p+q)^2+4}{2(p+q)} =p\\(p+q)^2+4=2p(p+q)\\p^2+q^2+2pq+4-2p^2-2pq=0\\q^2-p^2+4=0\\q^2=p^2-4$

6 0

2 years ago

I need help with 5 1\2× 3 1\4 =?

sattari [20]

5 1/2 * 3 1/4

1 + 5 . 2/2 * 1 + 3 . 4/4 = 11/2 * 13/4 = 11 . 13/2 . 4 = 143/8 = 7 + 17 . 8/8 = 17 7/8

= 17 . 875

Detailed explanation of solution:

5 1/2 * 3 1/4

Transform the first mix number to improper fraction:

5 1/2 = 1 + 5 . 2/2 = 11/2

Transform the second mix number to improper fraction:

3 1/4 = 1 + 3. 4/4 = 13/4

Multiplying two fractions:

11/2 * 13/4 = 11 . 13/2 . 4 = 143/8

Since the numerator is greater than the denominator, We convert the improper fraction to mix fraction:

143/8 = 7 + 17.8/8

= 17 7/8 (Decimal: 17. 875)

Hope that helps!!!!!! ( Answer: 17 7/8, (Decimal: 17.875)

3 0

3 years ago

What are the solutions to the equation (x-6)(x+8)=0?

Zepler [3.9K]

Answer:

x = 6, -8

Step-by-step explanation:

If (x - 6)(x + 8) = 0, that would imply that either (x - 6) or (x + 8) would equal zero. Using this, we can find that solving the two equations:

x - 6 = 0

and

x + 8 = 0

would yield the two solutions to the equation.

x - 6 = 0

Add 6 to both sides of the equation.

x = 6

So one of the solutions would be x = 6.

x + 8 = 0

Subtract 8 from both sides of the equation.

x = -8

So the other solution would be x = -8.

The two solutions are x = 6 and x = -8.

I hope you find my answer and explanation to be helpful. Happy studying.

6 0

3 years ago