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ki77a [65]
2 years ago
15

X-(9x-10)+11=12x+3(-2x+ 1/3)

Mathematics
1 answer:
morpeh [17]2 years ago
8 0
X - (9x - 10) + 11 = 12x + 3(-2x + \frac{1}{3} ) equals x = \frac{10}{7} .

First, simplify brackets. / Your problem should look like: x - 9x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ). 
Second, simplify x - 9x + 10 + 11 to -8x + 10 + 11. / Your problem should look like: -8x + 10 + 11 = 12x + 3(-2x + \frac{1}{3} ).
Third, simplify -8x + 10 + 11 to -8x + 21. / Your problem should look like: -8x + 21 = 12x + 3(-2x + \frac{1}{3} ).
Fourth, expand. / Your problem should look like: -8x + 21 = 12x - 6x + 1.
Fifth, simplify 12x - 6x + 1 to 6x + 1./ Your problem should look like: -8x + 21 = 6x + 1.
Sixth, add 8x to both sides. / Your problem should look like: 21 = 6x + 1 + 8x.
Seventh, simplify 6x + 1 + 8x to 14x + 1. / Your problem should look like: 21 = 14x + 1.
Eighth, subtract 1 from both sides. / Your problem should look like: 21 - 1 = 14x.
Ninth, simplify 21 - 1 to 20. / Your problem should look like: 20 = 14x.
Tenth, divide both sides by 14. / Your problem should look like: \frac{20}{14} = x.
Eleventh, simplify \frac{20}{14} to \frac{ 10}{7} . / Your problem should look like: \frac{10}{7} = x.
Twelfth, switch sides. / Your problem should look like: x = \frac{10}{7} which is your answer.

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Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x
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The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is \mathbf{y=-\frac{2}{3}x+3 }

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: y=mx+b where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation  y=mx+b where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

y=mx+b\\y=-\frac{2}{3}x+3

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