DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Which equation is not equvilant It is c
Answer:
c<15
Step-by-step explanation:
2x+17 < 13
Answer:
Area = 112cm^2
Step-by-step explanation:
Area = (a + b)*h / 2
M = (a + b) / 2
14 = (a + b) /
2*14 = a + b
28 = a + b
Area = 28*8 / 2
Area = 112 cm^2
