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Olenka [21]
3 years ago
8

Ellen bought 3 greeting cards for $3 each.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0

Answer:

(3×3)+2=11

$11

Step-by-step explanation:


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Mason has a collection of 49¢ stamps, 20¢ stamps, and 34 stamps worth $23.55. He has 56 total 49¢ and 20+ stamps and the number
tatuchka [14]

Answer:

Mason has

  • 16 20¢ stamps;
  • 25 3¢ stamps;
  • 40 49¢ stamps.

Step-by-step explanation:

Let x be the number of 20¢ stamps, then the number of 3¢ stamps is  x + 9.

Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.

Amounts:

  • in 49¢: 49(56-x) cents;
  • in 20¢: 20x cents;
  • in 3¢: 3(x+9) cents.

Total amount:

  • 49(56-x)+20x+3(x+9);
  • $23.55.

Hence,

49(56-x)+20x+3(x+9)=2,355\\ \\2,744-49x+20x+3x+27=2,355\\ \\-49x+3x+20x=2,355-2,744-27\\ \\-26x=-416\\ \\26x=416\\ \\x=16

Mason has

  • 16 20¢ stamps;
  • 25 3¢ stamps;
  • 40 49¢ stamps.
5 0
3 years ago
If the dimensions of a circle are tripled, the area of the resulting circle will also be three times larger.
Arturiano [62]

Answer:

the answer in false

Step-by-step explanation:


8 0
3 years ago
The stores markup on a wholesale item is 40%. The store is currently having a sale, and the item sales for 25% off the retail pr
Maurinko [17]

Answer:

75%

Step-by-step explanation:

7 0
3 years ago
I will give branliest to the first person to answer!
lara31 [8.8K]

Answer:

1: 10x-5

2: 6.5w-3y

3: 15+3n

4: not sure

8 0
3 years ago
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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