Answer
Find out the length of OP .
To prove
As given
In △JKL, JO=44 in.
Now as shown in the diagram.
JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .
Thus O be the centroid of the △JKL .
The centroid divides each median in a ratio of 2:1 .
Let us assume x be the scalar multiple of the OP and JO .
As given
JO = 44 in
2x = 44
x = 22 in
Thus the length of the OP IS 22 in .
Answer:
95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
Data: 5, 15, 12, 22, 27
mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months
sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months
n = 5
degree of freedom = n-1 = 5-1 = 4
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776
E = t×sd/√n = 2.776×7.68/√5 = 9.53 months
Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months
Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months
95% confidence interval is (6.67, 25.73)
Like in real life problems?
if yes then when conducting a survey, when grading quizzes/assignments, etc
Answer:
Turn off battery supply → The electromagnet turns off.
Place a magnet care inside the coil of wire → The strength of the electromagnet increases.
Change the direction in which the current flows → The poles of the electromagnet reverses
