The SSS proof used the rigid transformations illustrated here. Which transformations are used?

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

castortr0y [4]

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

$F=ma$

Part a) Solve this equation for a

$F=ma$

Divide both sides by the mass

$a=\frac{F}{m}$

therefore

the answer part a) is equal to

$a=\frac{F}{m}$

Part b) Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

$a=\frac{F}{m}$

in this problem

we have

$F=25\\m=10$

Substitute the values n the formula

$a=\frac{25}{10}$

$a=2.5$

therefore

the answer part b( is equal to

$a=2.5$

Part c) Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

$F=ma$

Solve for m

Divide both sides by the acceleration

$m=\frac{F}{a}$

in this problem

we have

$F=25\\a=5$

Substitute the values n the formula

$m=\frac{25}{5}$

$m=5$

therefore

the answer Part c) is

$m=5$

5 0

3 years ago

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What would you have to do to change 10 cubic feet into cubic inches?

Alina [70]

A. Divide by 46,656

B. Multiply by 1,728

C. Divide by 1,728

D. Multiply by 46,656

THE ANSWER IS B MULTIPLY BY 1,728

5 0

3 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago

Encuentra tres números enteros positivos consecutivos, tal que el cuadrado del primero se igual al tercero. Determina el número

myrzilka [38]

I don’t speak Spanish

7 0

3 years ago

HURRY plzz Identify to corresponding side to side HG.

a_sh-v [17]

Answer:

it would be EC (B)

Step-by-step explanation:

5 0

3 years ago

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