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kumpel [21]
3 years ago
8

Se distribuyen 400 bolsas en tres urnas sabiendo que la primera tiene 80 menos que la segunda y esta tiene 60 menos que la terce

ra, averigua cuántas bolsas tiene cada una.
Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer:

Primeras urnas = 60 bolsas

Segundas urnas = 140 bolsas

Terceras urnas = 200 bolsas

Step-by-step explanation:

Deje que las urnas se representen de la siguiente manera

Primeras urnas = a

Segundas urnas = b

Terceras urnas = c

Se nos dice en la pregunta

400 bolsas se distribuyen en tres urnas

Por lo tanto,

a + b + c = 400 bolsas ......... Ecuación 1

Por la pregunta sabemos que

1) El primero tiene 80 menos que el segundo

a = b - 80

2) Y este segundo tiene 60 menos que el tercero

b = c - 60

Por tanto, c = b + 60

Por lo tanto, sustituimos b - 80 por ayb + 60 por c en la Ecuación 1

a + b + c = 400 bolsas ......... Ecuación 1

b - 80 + b + b + 60 = 400 bolsas

Recopilar términos similares

b + b + b - 80 + 60 = 400 bolsas

3b = 400 + 80 - 60

3b = 420

b = 420/3

b = 140 bolsas

Por lo tanto, el número de bolsas en la segunda urna = 140 bolsas

Dado que a = b - 80

a = 140 bolsas - 80

a = 60 bolsas

Por lo tanto, el número de bolsas en la primera urna = 60 bolsas

Dado que c = b + 60

b = 140 bolsas

c = 140 + 60

c = 200 bolsas.

El número de bolsas en las terceras urnas = 200 bolsas.

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Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

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Going by the illustration in the question, the perimeter is

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However, we a given the mean perimeter of the frame which are:

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Case 2: We can simply say:

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Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

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The mean of side frame/bars  =  44 cm

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OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

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