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3 years ago

What is the unit rate 3 for $5 4 for$6

2 answers:

5 0

You have two separate problems here.

a) 3 for $5 needs to be expressed as cost per unit. Write $5/(3 units), and then simplify. Here the unit rate is ($5/3) / unit, or $1.67 per unit.

b) 4 for $6: Write $6/(4 units), and then reduce to lowest terms:
(6/4) dollars per unit, or $1.50/unit

Elena L [17]3 years ago

4 0

The unit rate for 3 for $5 is around $1.70 or $1.60

The unit rate for 4 for $6 is $1.50

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Mr. Wong cuts a coil of wire into two pieces in the ratio of 3:4. The length of the longer piece is 32 centimeters. What is the

zheka24 [161]

Answer:

56 cm

Step-by-step explanation:

The ratio of the lengths of the pieces is 3:4.

The longer piece is 32 cm.

We set up a proportion to find the length of the smaller piece.

Let the length of the smaller piece be x.

3 is to 4 as x is to 32

3/4 = x/32

4x = 3 * 32

4x = 96

x = 24

The smaller piece is 24 cm.

24 cm + 32 cm = 56 cm

6 0

3 years ago

Read 2 more answers

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

Six friends attend a party. They form pairs for a game. How many different pairs are possible?

Leona [35]

Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:

1. ABC against DEF

2. ABD against CEF

3. ABE against CDF

4. ABF against CDE

5. ACD against BFE

6. ACE against BDF

7. ACF against BDE

8. ADE against BCF

9. ADF against BCE

10. AEF against BCD

I believe there are 12 combinations... I just can't think of the last 2 though.

5 0

3 years ago

Equation of a line with slope -1 and y intercept 0,-2

hram777 [196]

Answer:

y = - x - 2

Step-by-step explanation:

y=mx+b

m refers to slope

b refers to y intercept

y = (-1)x + (-2)

y = - x - 2

8 0

3 years ago

Read 2 more answers

A tank was filled with 4 and half litres of water. 1.175 litres of water was poured out from the tank. How much water was left i

serg [7]

4-1.175=2.825
There was 2.825 liters left in the tank.
Hope this helps.

7 0

3 years ago