<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>
You know the area, so you can use the area formula A = 1/2(a+b) (a and b being the parallel sides AB and CD)
So, set 32.5 = 1/2 (AB +CD)
substitute --> 32.5 = 1/2( x+(x+1) )
simplify --> 32.5 = (2x+1)/2
simplify again --> 65 = 2x +1 --> 64 =2x --> 32 =x
Now that you have x, you can substitute it into the formula for your height (x-1) to get 31
63 and 65 are the two whole numbers
Answer:
Step-by-step explanation:
Distance formula:
(1-(-3))^2 - (-2-4)^2 = 16 + 36 = 20