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sp2606 [1]
3 years ago
15

SD and SG are tangent to ⊙ K. Identify SG. HELP!!

Mathematics
1 answer:
defon3 years ago
7 0

Answer:

63

Step-by-step explanation:

Tangents drawn from external point to a circle are congruent.

Therefore,

SG = SD

8x - 9 = 5x + 18

8x - 5x = 9 + 18

3x = 27

x =  \frac{27}{3}  \\ x = 9 \\ SG = 8x - 9  \\ SG =8 \times 9 - 9\\ SG =72 - 9 \\  \huge \red{ \boxed{SG =63}}

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