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Juliette [100K]
3 years ago
15

When s is the open hemisphere x 2 + y 2 + z 2 = 1, z ≤ 0 , oriented by the inward normal pointing to the origin, then the bounda

ry orientation on ∂s is clockwise. true or false?

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0
The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called N, using the Right-hand rule <span>the boundary orientation is </span>counterclockwise.

Therefore, the answer above False

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Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)
inessss [21]

Answer:

The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

Step-by-step explanation:

Find a function rule for the line that passes through the origin (0,0) and the point (5, - 13)

The function rule is of form: \mathbf{y=mx+b}

where m is slope and b is y-intercept

Finding slope:

The formula used to find slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=0, y_1=0, x_2=5, y_2=-13

Putting values and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{-13-0}{5-0}\\Slope=\frac{-13}{5}\\Slope=-\frac{13}{5}

Finding y-intercept

We will use point(0,0) to find y-intercept

y=mx+b\\0=-\frac{13}{5}(0)+b\\0=0+b\\b=0

So, y-intercept is 0

The Function rule for line having slope m=-13/5 and y-intercept b=0:

y=mx+b\\y=-\frac{13}{5}x+0\\y=-\frac{13}{5}x

So, The Function rule for line is: \mathbf{y=-\frac{13}{5}x}

Option A is correct option.

6 0
2 years ago
Help me please i neeeeeeeeed to get this right
Georgia [21]

Answer:

d)96π

Step-by-step explanation:

Given:

Cyliner with radius,a= 4

Height b=8

Surface area of cylinder, A=2πrh+2πr^2

=2π(rh+r^2)

=2π(4(8) + 4^2)

= 2π(32+16)

 =2π(48)

 =96π !

8 0
2 years ago
Read 2 more answers
suppose you have a dime, two pennies, and a quarter. one of the pennies was minted in 1976, and the other one was minted in 1992
notsponge [240]

The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

<h3>How to Solve Counting Problems?</h3>

A) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins. Let us label the dime as D, the penny as P, the quarter minted in 1976 as Q1 and the quarter minted in 1992 as Q2.

Now, if you choose one coin, you could choose either D, P, Q1, or Q2. This gives us 4 possible sets.

If you choose two coins, you choose the following sets of coins: DP, DQ1, DQ2, PQ1, PQ2, Q1Q2. This gives us 6 possible sets.

If you choose three coins, you could the following sets of coins: DPQ1, DPQ2, DQ1Q2, PQ1Q2. This gives us 4 possible sets.

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible set.

Therefore, the total number of different sets of coins you can form is 4 + 6 + 4 + 1 = 15 different sets of coins can be formed.

b) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins.

If you choose one coin you could choose either D, P, Q1, or Q2. However, since Q1 and Q2 give us the same sum, they are effectively the same set. This gives us 3 possible sums (ten cents, one cent, or twenty-five cents.)

If you choose two coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DP, DQ, PQ, Q1Q2. This gives us 4 possible sums (11 cents, 35 cents, 26 cents, or fifty cents.)

If you choose three coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DPQ, DQ1Q2, PQ1Q2. This gives us 3 possible sums (36 cents, 60 cents, or 51 cents).

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible sum (61 cents.)

Therefore, the total number of different sums of coins you can form is 3 + 4 + 3 + 1 = 11 different sums of money can be produced.

c) The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

Read more about Counting Problems at; brainly.com/question/13875198

#SPJ1

3 0
1 year ago
What is the result of substituting for y in the bottom equation?
jeka57 [31]
The answer is the option A, which is: A. x-7=x²+2x-4
 The explanation is shown below:
To solve this problem you must apply the proccedure shown below:
 1. You have the following system equations given in the problem above:
 <span>y=x-7
 y=x²+2x-4
2. Therefore, when you substitute for y in the bottom equation, you obtain:
 </span>x-7=x²+2x-4
8 0
3 years ago
Read 2 more answers
Three different golfers played a different number of holes today. Rory played 999 holes and had a total of 424242 strokes. Alici
Marat540 [252]

Golfer had the lowest number of strokes per hole is <u>Alicia </u> = 4.

<u>Step-by-step explanation:</u>

We have , Three different golfers played a different number of holes today. Rory played 999 holes and had a total of 424242 strokes. Alicia played 181818 holes and had a total of 797979 strokes. Rickie played 272727 holes and had a total of 123123123 strokes. We have to find  , Which golfer had the lowest number of strokes per hole :

<u>Rory:</u>

Number of strokes per hole = \frac{424242}{999}  = 425

<u>Alicia:</u>

Number of strokes per hole = \frac{797979}{181818}  = 4

<u>Rickie:</u>

Number of strokes per hole = \frac{123123123}{272727}  = 451

∴ Golfer had the lowest number of strokes per hole is <u>Alicia </u> = 4.

8 0
3 years ago
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