When s is the open hemisphere x 2 + y 2 + z 2 = 1, z ≤ 0 , oriented by the inward normal pointing to the origin, then the bounda
ry orientation on ∂s is clockwise. true or false?
1 answer:
The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called N, using the Right-hand rule <span>the boundary orientation is </span>counterclockwise.
Therefore, the answer above False
Therefore, the answer above False
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Answer:
a)
b)
Step-by-step explanation:
a)
1. Distribute the second power (2) outside the first pair of parenthesis:
=
2. Distribute the third power (3) outside the second pair of parenthesis:
=
3. Combine like terms:
--------------------------------------------
b)
1. Factor the number 6 (= 2 · 3):
2. Cancel the common factor (2):
3. Cancel out in the numerator an denominator:
hope this helps!