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bazaltina [42]
3 years ago
12

How do you convert fractions to decimals and percents

Mathematics
1 answer:
Levart [38]3 years ago
4 0
Well when you convert fractions to decimals, you simply divide the numerator by the dominator. 
To convert decimals to percents, you take the fraction and divide the numerator by the dominator and times that by 100. 
For example, 4/25*100=16%
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if α,β are the roots of the equation x^{2}-3x+2=0 form an equation whose roots are (α+β)² & (α-β)²
GuDViN [60]

<u>Solution</u><u>:</u><u>-</u>

Let's find roots of x² - 3x + 2

=> x² - 3x + 2 = 0.

=> x² - x - 2x + 2 = 0.

=> x ( x - 1 ) -2 ( x - 1) = 0.

=> ( x - 1 ) ( x - 2 ) = 0.

=> x = 2, 1.

Now

  • ( a + ß )² = (2+1)²=3²=9
  • ( a - ß )² = ( 2 - 1 )² = 1² = 1.

So , equⁿ would be ,

=> x² - ( 9 + 1)x + 9×1=0.

<u>=> x² - 10x + 9=0.</u>

6 0
3 years ago
a math test has 25 questions on it if a student incorrectly answers 5 questions on the test what percentage of problems are corr
ikadub [295]

The student would get an 80%.

Since 5 is 20% of 25, subtract 20 from 100 and you get 80%

7 0
3 years ago
Find three consecutive integers whose sum is -354.
Butoxors [25]

Answer:

1 + 1 = 11

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Identify the three similar right triangles in the given diagram.
irga5000 [103]

Answer:

B. ΔABD, ΔADC, ΔDBC

Step-by-step explanation

Step -1 In ΔABD and ΔADC (from figure).

∠DAB=∠CAD (common in both triangles) ,

∠DBA=∠CDA =90 degree, and

∠BDA=∠DCA (rest angle of the two triangles).

therefore ΔABD similar to ΔADC (by AAA similarity theorem).

Step -2 In ΔDBC and ΔADC (from figure).

∠DCB=∠ACD (common in both triangles) ,

∠DBC=∠ADC =90 degree, and

∠CDB=∠CAD (rest angle of the two triangles).

therefore ΔDBC similar to ΔADC (by AAA similarity theorem).

Step -3 In ΔABD and ΔDBC (from figure).

∠BDA=∠BCD (because , ∠ACD=ADB from stap-1 and ∠ACD=∠BCD from figure) ,

∠DBA=∠CBD =90 degree, and

∠BAC=∠BDC (rest angle of the two triangles).

therefore ΔABD similar to ΔDBC (by AAA similarity theorem).

In the above step- ΔABD similar to ΔADC, ΔDBC similar to ΔADC and ΔABD similar to ΔDBC.

Hence ΔABD, ΔADC, ΔDBC similar to each other in the given figure.

4 0
3 years ago
I need help with question 18 PLS!!!!
dolphi86 [110]

Answer:

162

Step-by-step explanation:

( -a ) ( b ) ( -a + b )

-6 ( 3 ) ( -6 + -3 )

-6 ( 3 ) ( -9 )

 - 18 ( -9 )

     162

6 0
3 years ago
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