In the following Laplace transform, how do you get rid of the cos(2at)*sin(at)?
1 answer:
<span>sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]</span>
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A. 6.4/2
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Answer:
um thanks i guess
Step-by-step explanation:
All corners are 90o angles.
Slope= y2-y1/ x2-x1
= -1-2/-1+3
= -3/2 is the answer
Answer:
x-intercepts
y=0
0=(x+5)(x-1)
x=-5 or x=1
y-intercept
y=(0^2)+4(0)-5
y= -5
