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Tamiku [17]
3 years ago
12

Which of the following quantities are continuous?

Mathematics
2 answers:
Oxana [17]3 years ago
4 0

Answer:

A. only II

Step-by-step explanation:

Mathematics calculus differentiates things into discrete and continuous. Discrete things have indivisible units, the example will be how many dogs in a village. There is no half dog, it's either one, two, etc. But the distance covered by train can be written as half miles, it's divisible unit.  

The number of books and bracelets also discrete, thus the answer is A.

zalisa [80]3 years ago
4 0

Answer:

Only ll

Step-by-step explanation:

Discrete quantities are countable and restricted to specific values.

A continuous quantity is not restricted to specific values and can occupy any value over a continuous range.

The population of dogs in a village can be any positive integer. Since the population is countable and can be represented by a set of specific values, the population of dogs in a village is a discrete quantity.

The distance covered by a train can be any real number. Since distance is a variable that can occupy any value over a continuous range, the distance covered by a train can be classified as a continuous quantity.

The number of books shelved in the fiction section of a library can be any positive integer. Since the number of books are countable and can be represented by a set of specific values, the number of books shelved in the fiction section of a library is a discrete quantity.

The number of bracelets sold can be any positive integer. Since the number of bracelets are countable and represented by a set of specific values, the number of bracelets sold is a discrete quantity.

Therefore, only II represents a continuous quantity

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2500m2

Step-by-step explanation:

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The line l with equation x - 2y + 2 = 0 crosses the y-axis at the point P. The line
Sauron [17]

Answer:

Area of ΔPQR is 28 units²

Step-by-step explanation:

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-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point P( 0, b)

x-2y+2 = 0, subtract x and 2 from both sides

-2y = -x-2, divide by -2 both sides

y= (1/2)x +1 so b=1 and P (0, 1)

-Q  is the point with coordinates ( 0, y-intercept for line 3x+y -15 =0)

-rearrange the equation in the point-slope form y=mx+b  to find the y coordinate of the point Q( 0, b)

3x +y -15 =0, subtract 3x and add 15 to both sides

y= -3x +15 so b=15 and Q(0,15)

-R is the intersection of the two lines so is the solution of the system of equations y= (1/2)x +1 and y= -3x +15

(1/2)x +1 =  -3x +15, add 3x and subtract1

(1/2) x+3x = 15-1, combine like terms

(7/2)x = 14 , multiply both sides by 2

7x = 28, divide both sides by 7

x= 4

y= (1/2)x +1 = (4/2) +1 =3 so R(4,3)

- the area of ΔPQR is (base *height)/2

base= 15-1= 14

height = 4

A= (14*4)/2 = 14*2 = 28

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