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Olegator [25]
3 years ago
12

What inequality is graphed below? x < -4 x ≤ -4 x ≥ -4 x > -4

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

The answer is x>-4

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6. Write an equation of a line that is Parallel to the line: y = 3x -3
jeka94

Answer:

3x - y -6 = 0

Step-by-step explanation:

We need to find the Equation of the line parallel to the given equation of line . The given equation of the line is ,

\rm\implies y = 3x - 3

<u>Slope </u><u>Intercept</u><u> Form</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = mx + c

where ,

  • m is slope
  • c is y intercept .

Therefore , the Slope of the line is 3 . Let the parallel line passes through ( 3,3) . We know that the parallel lines have same slope . Therefore the slope of the parallel line will also be 3 .

<u>Using</u><u> point</u><u> slope</u><u> form</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y - y_1 = m ( x - x_1)  \\\\\rm\implies y - 3 = 3( x - 3 ) \\\\\rm\implies y -3 = 3x -9 \\\\\rm\implies 3x -y -9+3=0\\\\\rm\implies \boxed{\rm\red{ 3x -y -6=0}}

3 0
3 years ago
you put 500$ in your bank account. With an intrest rate of 5% how long will it take for the account to reach 600$?
Sergeeva-Olga [200]
4 1/2 years
hope this helped
3 0
3 years ago
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the
nalin [4]

Answer:

$519

Step-by-step explanation:

Given the amount of profit made expressed as y=-2x^2+105x-859

At maximum profit, dy/dx = 0

dy/dx = -4x + 105

0 = -4x + 105

4x = 105

x = 105/4

x = 26.25

Substitute into the original function

y=-2x^2+105x-859

y=-2(26.25)^2+105(26.25)-859

y = - 1,378.125+2,756.25-859

y = 519.125

Hence the maximum amount of profit the company can make is $519

8 0
3 years ago
A coin is tossed 5 times and a tail is the outcome each time. what is the probability of getting a tail on the sixth throw
Norma-Jean [14]
I believe it would be
1/5
5 0
3 years ago
What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?
Dafna11 [192]

Answer:

The horsepower required is 235440 watt.

Step-by-step explanation:

To find : What horsepower is required to lift an 8,000 pound aircraft six feet in two minutes?

Solution :

The horsepower formula is given by,

W=\frac{mgh}{t}

Where, W is the horsepower

m is the mass m=8000 pound

g is the gravitational constant g=9.81

t is the time t= 2 minutes

h is the height h=6 feet

Substitute all values in the formula,

W=\frac{8000\times 9.81\times 6}{2}

W=\frac{470880}{2}

W=235440

Therefore, The horsepower required is 235440 watt.

6 0
3 years ago
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