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Olegator [25]
3 years ago
12

What inequality is graphed below? x < -4 x ≤ -4 x ≥ -4 x > -4

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0

Answer:

The answer is x>-4

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Easy question. Get your points for the day along with brainliest (15 more points) !
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Answer:

its c......................................................

Step-by-step explanation:

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3 years ago
Round 8.96278650871 to the nearest millionth.
Andru [333]

the answer is 8.962790 because it is rounded to the nearest millionth

I hope this helps you

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3 years ago
What is the solution to the system of equations below?
Karolina [17]

Answer:

The solution is the point (18,0)

Step-by-step explanation:

we have

y=-\frac{1}{3}x+6 -----> equation A

y=\frac{1}{3}x-6 -----> equation B

Solve the system by substitution

substitute equation B in equation A

\frac{1}{3}x-6=-\frac{1}{3}x+6

solve for x

Adds (1/3)x both sides

\frac{1}{3}x-6+\frac{1}{3}x=6

\frac{2}{3}x-6=6

Adds 6 both sides

\frac{2}{3}x=6+6

\frac{2}{3}x=12

x=12(3)/2\\x=18

<em>Find the value of y</em>

substitute the value of x in equation A or equation B

y=-\frac{1}{3}(18)+6=0

therefore

The solution is the point (18,0)

3 0
3 years ago
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Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi
lara [203]

For each curve, plug in the given point (x,y) and check if the equality holds. For example:

(I) (2, 3) does lie on x^2+xy-y^2=1 since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative \frac{\mathrm dy}{\mathrm dx}, and evaluate it for the given point (x,y). This is the slope of the tangent line at the point. For example:

(I) The derivative is

x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}

so the slope of the tangent at (2, 3) is

\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74

and its equation is then

y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, -\frac1{\frac{\mathrm dy}{\mathrm dx}}. For example:

(I) The tangent has slope 7/4, so the normal has slope -4/7. Then the normal line has equation

y-3=-\dfrac47(x-2)\implies y=-\dfrac47x+\dfrac{29}7

3 0
3 years ago
Find the circumference of the circle.
OLga [1]

Circumference (C) = 2 π·r   ; where r is the radius = diameter(d)/2

C = 2 π·(14/2)

  =2 π·(7)

  = 14π

3 0
3 years ago
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