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goldenfox [79]
4 years ago
5

Factor 16x^2 + 49. Check your work.

Mathematics
1 answer:
Shtirlitz [24]4 years ago
4 0

Answer:

16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})

Step-by-step explanation:

Given : Expression 16x^2+49

To find : Factor the expression ?

Solution :

The given expression is a quadratic function y=ax^2+bx+c the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

On comparing with general form,

a=16, b=0, c=49

Substitute in the formula,

x=\frac{-0\pm\sqrt{0^2-4(16)(49)}}{2(16)}              

x=\frac{\pm\sqrt{-3136}}{32}          

x=\frac{\pm56i}{32}      

x=\frac{56i}{32},\frac{-56i}{32}      

x=\frac{7i}{4},\frac{-7i}{4}              

Factors are (x-\frac{7i}{4}),(x+\frac{7i}{4})        

Therefore, 16x^2+49=(x-\frac{7i}{4})(x+\frac{7i}{4})    

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and


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EXPLANATION




17x-3y=4---(1)


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Let us make y the subject and call it equation (2)


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We put equation (2) in to equation (1)




17(\frac{1}{2}+2y)-3y=4


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Simplify to get,



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Divide both sides by 31,



y= \frac{-9}{2} \div 31



y= \frac{-9}{2} \times \frac{1}{31}




y= \frac{-9}{62}


We put this value in to equation (2) to get,



x=\frac{1}{2}+2\times -\frac{9}{62}




x=\frac{1}{2} -\frac{18}{62}


We collect LCM to obtain,



x=\frac{31-18}{62}



x=\frac{13}{62}








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