Someone plz help ill really appreciate it

Mathematics

1 answer:

julia-pushkina [17]2 years ago

6 0

I believe it is A because you add all of the numbers together and get 47. Then you divide by the numbers that appear often. In this case it is 2. Divide 47 by 2 and you get about 22 or 23.

Hope this helps and is correct :)

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Step-by-step explanation:

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$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$