Answer:
In the 3rd and 4th quadrants of the coordinate system
ie π < θ < 2π. At π and 2π the sine values are zero
Step-by-step explanation:
Answer:
The answer is B
Step-by-step explanation:
r = c/2π
c = 16π
r = 16π/2π
= 8
Answer:
Step-by-step explanation:
x(3x+2)=16
3x²+2x-16=0
3x²+8x-6x-16=0
x(3x+8)-2(3x+8)=0
(3x+8)(x-2)=0
either 3x+8=0
x=-8/3(rejected as width can't be negative)
x-2=0
x=2
so width=2
length=3×2+2=6+2=8
Alright so the parentheses mean (x, y) so basically you have to plug in the numbers in parentheses into the equation so here's what I got:
a. i
b. iv
c. ii
d. v
So then e must be iii, let’s check:
y = -x + 1
.5 = -.5 + 1 ✔️
.75 = -.25 + 1 ✔️
.875 = -.125 + 1 ✔️
So that’s how you would solve those equations. Hope this helps.
