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Sloan [31]
3 years ago
5

{x}^{2} + 13y)(4x \times 2xy)" alt="(12 {x}^{2} + 13y)(4x \times 2xy)" align="absmiddle" class="latex-formula">
need help solving? can anyone help​
Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

96x^4y+104x^2y^2

is the simplified form of

your given problem:

(12x^2+13y)(4x \times 2xy).

Step-by-step explanation:

So the given problem is this:

(12x^2+13y)(4x \times 2xy)

I'm going to do the multiplication in the second ( ).

Nothing can be done in the first ( ) because the operation is addition and those two terms aren't like terms.

(12x^2+13y)(8x^2y)

I got x^2 because of x(x) part.

Now we get to distribute 8x^2y to both terms in the ( ).

12x^2 \cdot 8x^2y+13y \cdot 8x^2y

Adding exponents on bases that have the same variable:

96x^4y+104x^2y^2

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In circle O shown, RS intersects chord PQ at point N such that measure PR =34 and measure of angle PNR = 45 degrees. Which of th
torisob [31]

Answer:

2. 45

Step-by-step explanation:

i got  this right today lol

5 0
3 years ago
In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.
inn [45]

Answer:

a) The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b) The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c) The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d) The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

Standard error:

The standard error is:

s = \sqrt{\frac{\pi(1-\pi)}{n}}

Margin of error:

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = zs

The confidence interval is:

Sample proportion plus/minus margin of error. So

(\pi - M, \pi + M)

In a simple random sample of 1500 young Americans 1305 had earned a high school diploma.

This means that n = 1500, \pi = \frac{1305}{1500} = 0.87

a. What is the standard error for this estimate of the percentage of all young Americans who earned a high school diploma?

s = \sqrt{\frac{\pi(1-\pi)}{n}} = \sqrt{\frac{0.87*0.13}{1500}} = 0.0087

0.0087*100% = 0.87%.

The standard error for this estimate of the percentage of all young Americans who earned a high school diploma is 0.87%.

b. Find the margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Then

M = zs = 1.96*0.0087 = 0.0171

0.0171*100% = 1.71%

The margin of error, using a 95% confidence level, for estimating the percentage of all young Americans who earned a high school diploma is of 1.71%.

c. Report the 95% confidence interval for the percentage of all young Americans who earned a high school diploma.

87% - 1.71% = 85.29%

87% + 1.71% = 88.71%.

The 95% confidence interval for the percentage of all young Americans who earned a high school diploma is (85.29%, 88.71%).

d. Suppose that in the past, 80% of all young Americans earned high school diplomas. Does the confidence interval you found in part c support or refute the claim that the percentage of young Americans who cam high school diplomas has increased? Explain.

The lower bound of the confidence interval is above 80%, which means that the confidence interval supports the claim that the percentage of young Americans who cam high school diplomas has increased.

4 0
3 years ago
The graph of f(x) = (0.5)x is replaced by the graph of g(x) = (0.5)x − k. If g(x) is obtained by shifting f(x) down by 2 units,
zepelin [54]
K is the distance of the vertical translation.
Since you shifted the graph 7 units down, k will be equal to 7
So g(x) = (0.5)x - 7 is f(x) vertically translated 7 units down

If g(x) is obtained by shifting f(x) down by 7 units
meaning that
g(x)=(0.5)~~~~~7 units to the bottom from f(x)-k?

I can't explain but k=-7

it's g(x)=f(x)-(-7)
so the k=7.

f(x)-k=f(g)-7
the original function of f(x) is obtained by shifting f(g) 7 units down, or by -7
so x=7
5 0
4 years ago
Read 2 more answers
4: A school has 314 boys & 310 girls. If they are to be grouped into equal classes of 26 each , how many classes will there
kherson [118]

4: A school has 314 boys & 310 girls. If they are to be grouped into equal classes of 26 each , how many classes will there be?

314 boys + 310 girls = 624

If they are grouped into classes of 26 students each, how many class will there be?

130 students = 5 classes

Therefore

260 students = 10 classes

260 x 2 = 520 = 20 classes

26 x 24 = 624

Number of classes = 24

Question 5).

Jim worked 48 weeks last year. Each week he worked 38 hours. If he worked an additional 240 hours of overtime, how many hours did he work in all?

Solution:

48 weeks

24hrs × 7 = 168hrs

168 x 48 = 8,064

Additional 240hrs

= 168hrs = 7 days (a week)

240hrs - 168 = 72 (3days)

168 + 72

= 240hrs + 8, 064

= 8, 304 hrs

6 0
3 years ago
A book contains 256 pages. A school has 48 copies of this book. How many total pages are there in the books?
svp [43]

Answer:

The answer is 12,288

Step-by-step explanation:

Hope this right.But if it's not im so sorry.

<em>H</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>n</em><em>i</em><em>c</em><em>e</em><em> </em><em>d</em><em>a</em><em>y</em><em> </em><em>:</em><em>v</em>

8 0
4 years ago
Read 2 more answers
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