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victus00 [196]
3 years ago
11

Write the quadratic equation in factored form. Be sure to write the entire equation.

Mathematics
1 answer:
leonid [27]3 years ago
4 0

Glad they didn't have online homework when I was in school; what a pain to type this way.


x^2 - 5x - 24 = 0


We need two numbers that multiply to -24 and add to -5; it doesn't take too long to come up with -8 and 3.


(x-8)(x+3) = 0


That's the answer.


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Two functions are given.
ArbitrLikvidat [17]

Hi

f(x) = g(x)   if    -x²+3x-2   - ( -x+1) = 0

                      -x² +3x-2 +x-1 = 0

                      -x² +4x -3 = 0

To solve, tou have to use the general method of resolution of a quadratic fonction.  

To determine if it's has a solution in R, let's calculate  Δ

Δ = (4)² - 4 * (1) *(-3)

Δ = 16 +12

Δ= 28  

as Δ≥ 0  so  the function allow two solution within R  

so S 1 =  ( -4 +√28) / 2            S 2 =   (-4 -√28 ) /2

    S1 =   ( -4 + 2√7) /2            S2 =    (-4 - 2√7) /2

    S1 =    (2 (-2 +√7) /2            S2      2 (-2 -√7)   /2

    S1 =    -2 +√7                       S2 =      -2 -√7

So the two function  are equal   twice. one  for   x = -2 +√7  and second x = -2-√7

4 0
3 years ago
Towns P,Q,R and S are shown. Q is 35 km due East of P S is 15km due West of P R is 15km due South of P Work out the bearing of R
Anni [7]

Answer:

Part A

The bearing of the point 'R' from 'S' is 225°

Part B

The bearing from R to Q is approximately 293.2°

Step-by-step explanation:

The location of the point 'Q' = 35 km due East of P

The location of the point 'S' = 15 km due West of P

The location of the 'R' = 15 km due south of 'P'

Part A

To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that \overline{RP} = \overline{SP}, the right triangle ΔRPS is an isosceles right triangle

∴ ∠PRS = ∠PSR = 45°

The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°

Part B

∠PRQ = arctan(35/15) ≈ 66.8°

Therefore the bearing  from R to Q = 270 + 90 - 66.8 ≈ 293.2°

6 0
3 years ago
Denis let go of a penny at the top of a well and the penny fell straight down to the bottom of the well the top of the well was
Furkat [3]

Answer:

The distance between the top of the well and the bottom of the well was 12 1/2

Step-by-step explanation:

(a.k.a B) i did it and got it right :)

8 0
3 years ago
What is the value of y in the equation 5x + 2y = 20, when x = 0.3?
Nikolay [14]
Y=9.25 because inorder to solve this we need to first take 5*.3 which equals 1.5 now that we have this we can move on we now have the equation 1.5 + 2y = 20 so now we need to continue working on getting y by it self so we subtract 1.5 from each side and then that leaves us with 2y=18.5 now we divide by 2 which leaves us with y=9.25 enjoy=)
4 0
3 years ago
The sum of two consecutive integers is -239 find the two integers​
xenn [34]

Answer:

The two consecutive integers are -119 and -120

Step-by-step explanation:

As we know that these two integers are consecutive, that means that they will have a difference of 1. This means that we can find the two integers by adding 1 to the sum of -239 and then dividing it by two

1-239=-238\\\frac{-238}{2} =-119\\-119-1=-120

5 0
3 years ago
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