The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
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Answer:
The correct option is 1.
Step-by-step explanation:
If a quadratic equation is defined as
.... (1)
Then the sum of the roots is -b/a and the product of roots is c/a.
The given equation is
... (2)
From (1) and (2) we get a=3, b=11 and c=-4.
The sum of roots is
The sum of roots is 
.
Therefore the correct option is 1.
Answer:
56
Step-by-step explanation:
Isolate the variable (x). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 5 from both sides:
13 (-5) = (x/7) + 5 (-5)
13 - 5 = x/7
8 = x/7
Isolate the variable x. Multiply 7 to both sides:
8(7) = (x/7)(7)
8(7) = x
x = 8 * 7
x = 56
56 is your answer for x.
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Answer:
graph?
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
you take the positive value for it
f(-3) = |2×(-3)+1|+5 ➡ |-6+1| + 5 ➡ |-5|+5 = 5+5
