25% is the approximate production efficiency of this animal
Explanation:
Given ,
A ladybug eats 200 J of plant material
100 J is eliminated as feces
75 J are used in cellular respiration,
Now,
The approximate production efficiency of this animal :
200 - (100 +75) = 25 %
Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
Answer:
the last one because
Explanation:
matter is not created or destroyed so everything that you put in the solution will make up the mass
Answer:
They use their antlers to fight and establish dominance.
Explanation: