Answer:
<h2>Width = 7.6 ft.</h2><h2>Length = 12.7 ft.</h2>
Step-by-step explanation:
Perimeter of a rectangle (P) = 2L + 2W
where
P = 40.6 ft.
L = 2W-2.5
plugin values into the formula:
40.6 = 2(2W-2.5) + 2W
40.6 = 4W - 5 + 2W
40.6 + 5 = 6W
W = 45.6 / 6
W = 7.6 ft.
L = 2W-2.5
L = 2(7.6) - 2.5
L = 12.7 ft.
proof:
P = 2(12.7) + 2(7.6)
P = 40.6 ft.
Answer:
<u>₹4000</u>
Step-by-step explanation:
₹800/10 books
₹80/1 book
<u>(₹80/1 book)*(50) = ₹4000</u>
Answer:
the exact value of tan(-315) is 1
Answer:
in a file
ly/3fcEdSx
bit.
Step-by-step explanation:
Answer:
- high tide occurs at 12 noon and 12 midnight
- Low tide occurs at 6 a.m and 6 p.m
- maximum depth value = 20 ft
- Minimum depth value = 15 ft
Step-by-step explanation:
The depth is modelled as;
y = 20 + 5 cos (πt/6)
We are told that t = 0 represents 12:00 midnight.
This is high tide because at t = 0, the cos function will be at it's maximum value of 1 since cos 0 = 1.
Max depth value is;
y = 20 + 5(0)
y = 20 ft
Minimum depth value will be the low tide and it will be when the cos function is equal to -1.
Thus;
y = 20 + 5(-1)
y = 15 ft
Since t represents number of hours and since at 12 midnight, t = 0, thus; high tide will occur again at;
12 noon
Also, let's check for low tide.
Let's try t = 6 which means 6 a.m
Thus;
y = 20 + 5 cos (π(6)/6)
y = 20 + 5 cos π
Cos π has a value of -1
Thus;
y = 20 + 5(-1)
y = 20 - 5
y = 15 ft
Thus;
Low tide occurs at 6 a.m and 6 p.m
