Question

A triangle has height 4 ft and area 32 ft2. What is the lenght of the base?

Answer 1

$A=32ft^2 \\\\ A=\frac{b*h}{2} \\\\ \frac{b*4}{2}=32 \\\\ b=\frac{2*32}{4} \\\\ b=2*8 \\\\ \boxed{b=16ft}$

Answer 2

$Formula\ for\ area\ of\ triangle:\\\\ Area=\frac{1}{2}base*height\\\\ 32=\frac{1}{2}*4*base\\\\ 32=2base\ \ \ |Divide\ by\ 2\\\\ base=16ft\\\\ Length\ of\ base\ is\ equal\ to\ 16ft.$