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Nostrana [21]
3 years ago
14

What is the product of 3 1/2 x 1/5

Mathematics
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

7/10

Step-by-step explanation:

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NEED HELP DUE IN 10 MINUTES!!!
slavikrds [6]
Where is the question? I would be more than happy to help you but you did not post a question
3 0
2 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
Determine which of the following sets of ordered pairs represents a function
Illusion [34]

Answer:

B.

Step-by-step explanation:

Every answer besides B. has an input that repeats. A function contains inputs that have exactly one output. This means x values cannot have more than one y value.

8 0
3 years ago
2f = 8 It’s asking me to find an answer the answers aref = 16f = 10f = 6 f = 4
Naddika [18.5K]
\begin{gathered} 2f=8 \\ \text{Solving f} \\ f=\frac{8}{2} \\ f=4 \\ \text{The value of f is 4} \end{gathered}

3 0
10 months ago
Help me with this, please! Very thankful!
Naya [18.7K]
X. Y
12 —> 4
8 —> 8/3
13 —> 13/3

Substitute x values for y.
y = 1/3(12)
y=4
5 0
2 years ago
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