Then,
3^y = 7, is equivalent to y = log_3(7)
We need to find which graph goes like log_3(x). For x =3, log_3(3) = 1, for x = 9, lo_3(9)=2, so .....
The first one!
1 is the initial value because it started at 1 in the beginning, and it transfered up to 6,7.
All you need to know is that if the lines are the same and is not touching or intersecting then they are parallel. Parallel lines never intersect, those will be perpendicular lines.
It would most likely be (1).
(67 + 68 + 78 + x) / 4 = 70
(213 + x) / 4 = 70
213 + x = 70 * 4
213 + x = 280
x = 280 - 213
x = 67
(213 + x) / 4 = 79
213 + x = 79 * 4
213 + x = 316
x = 316 - 213
x = 103
lowest u can make is 67, highest u can make is 100