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4 years ago

AD is a common internal tangent to circles B and C. Find the length of the radius of circle B. Round to the nearest hundredth.

Mathematics

2 answers:

ycow [4]4 years ago

8 0

ΔABE ~ ΔDCE
AB=AE*DC/DE=18*4/6=12

ikadub [295]4 years ago

3 0

As AD is common tangent,

<BAE=90=<CDE

Also <BEA=<CED as they are opposite angles

By AAA, the two triangles, ABE and DCE, are similar

so AB/EA = DC/ED

AB = EA * DC/ED = 18 * 4/6

= 12

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3 years ago

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Step-by-step explanation:

$a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\$

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$a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\$

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3 years ago

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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