1/2 of 2 is 1 .
1/2 of 3 is (1 and 1/2).
1/2 of 4 is 2 .
Complete question is;
It took Priya 5 minutes to fill a cooler with 8 gallons of water from a faucet that was flowing at a steady rate. Let w be the number of gallons of water in the cooler after t minutes. Which of the following equations represent the relationship between w and t? Select all that apply
A) w = 1.6t
B) w = 0.625t
C) t = 1.6w
D) t = 0.625w
Answer:
Option A: w = 1.6t
& Option D: t = 0.625w
Step-by-step explanation:
We are told It took Priya 5 minutes to fill a cooler with 8 gallons of water at a steady rate.
Thus;
Rate of filling = 8 gallons/5 minutes = 1.6 gallons/minutes
Now, we are told that w is the number of gallons of water in the cooler after t minutes.
Thus, to find w, we will multiply the rate by t minutes.
w = 1.6 gallons/minutes × t minutes
w = 1.6t gallons
Or we can write as;
w/1.6 = t gallons
0.625w = t gallons
Therefore, options A & D are correct.
Answer:
went up a total of 4 degree at 2 degree a day
Answer:
I think it is MN and NP maybe
<h3>
<u>Correct Question :- </u></h3>
(a) 0
(b) 8000
(c) 8080
(d) 16000
Given that
We know
And
Also, given that
and
Now, Consider
![\sf \: = 20\bigg[ {a}^{2} + {b}^{2} + {c}^{2} + {d}^{2}\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7Ba%7D%5E%7B2%7D%20%2B%20%20%7Bb%7D%5E%7B2%7D%20%2B%20%7Bc%7D%5E%7B2%7D%20%2B%20%20%7Bd%7D%5E%7B2%7D%5Cbigg%5D)
We know,
So, using this, we get
![\sf \: = 20\bigg[ {(a + b)}^{2} - 2ab + {(c + d)}^{2} - 2cd\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28a%20%2B%20b%29%7D%5E%7B2%7D%20-%202ab%20%2B%20%20%7B%28c%20%2B%20d%29%7D%5E%7B2%7D%20-%202cd%5Cbigg%5D)
![\sf \: = 20\bigg[ {( - 20)}^{2} + 2(2020) + {(20)}^{2} - 2(2020)\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20%7B%28%20-%2020%29%7D%5E%7B2%7D%20%2B%20%202%282020%29%20%2B%20%20%7B%2820%29%7D%5E%7B2%7D%20-%202%282020%29%5Cbigg%5D)
![\sf \: = 20\bigg[ 400 + 400\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20400%20%2B%20400%5Cbigg%5D)
![\sf \: = 20\bigg[ 800\bigg]](https://tex.z-dn.net/?f=%20%5Csf%20%5C%3A%20%20%3D%2020%5Cbigg%5B%20800%5Cbigg%5D)
Hence,
<em>So, option (d) is correct.</em>
